Answer:
2/-3
Step-by-step explanation:
Hope this helped. And I know that you can choose more than one, but I'm pretty sure this is the only one that's equivalent to -2/3
Answer:
0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 3 cm and a standard deviation of 0.04 cm.
This means that 
What is the probability that a bolt has a length greater than 2.96 cm?
This is 1 subtracted by the p-value of Z when X = 2.96. So



has a p-value of 0.1587.
1 - 0.1587 = 0.8413
0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.
Answer:
36-e
Step-by-step explanation:
-
You know that 3 times 2 is 6 so 30'times 20 equals 60
<span>
the complete question in the attached figure</span>
The answer is the option A
9.9 grams
because the balance is accurate to the nearest 1/10 gram; thus, the <span>highest level of accuracy appropriate to the limitations of the balance is 0.10 gram (1/10)</span>