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aalyn [17]
2 years ago
15

Newton and descartes each have 42 glow in the dark stickers newton divides his into 6 equal groups descartes divides his into 7

equal groups who has more stickers in each group
Mathematics
2 answers:
LekaFEV [45]2 years ago
6 0

Newton has more stickers in each group if Newton and Descartes each have 42 glow-in-the-dark stickers newton divides his into 6 equal groups Descartes divides his into 7 equal groups.

<h3>What is a fraction?</h3>

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

It is given that:

Newton and Descartes each have 42 glow-in-the-dark stickers newton divides his into 6 equal groups Descartes divides his into 7 equal groups.

For Newton:

= 42/6

= 7

For Descartes:

= 42/7

= 6

Thus, Newton has more stickers in each group if Newton and Descartes each have 42 glow-in-the-dark stickers newton divides his into 6 equal groups Descartes divides his into 7 equal groups.

Learn more about the fraction here:

brainly.com/question/1301963

#SPJ2

Elodia [21]2 years ago
5 0

Answer:

newton

Step-by-step explanation:

first you have to divide Newtons stickers and get 7, then you divide Descartes stickers and get 6, so therefore Newton has more

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What is the GCF of 12m + 3mx?
zhenek [66]

Answer:

3m

Step-by-step explanation:

You can check

3m(4+x)

12m+3mx

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6 0
3 years ago
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Vince weighs 160 pounds, and his friend Nadir weighs 140 pounds. Nadir calculated that his weight on another planet would be abo
Ymorist [56]

Answer: 64 lbs

Step-by-step explanation:

I divided 56/140 and got 0.4. Then multiplied 0.4 by 160 and got 64. SOunds about right to me.

You can double check by multipling 0.4 by 140 and you get 56.

4 0
2 years ago
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The temperature of lake water over a period of time is shown in the graph below.
castortr0y [4]

Answer:

Answers are 3 AM ; 10 , 54

Step-by-step explanation:

We are given a graph.

Recording of temperature starts from 9 PM.

So from Graph,

Temperature ate 9 PM = 59°F

Temperature ate 11 PM = 54°F

Temperature ate 1 AM = 51°F

Temperature ate 3 AM = 50°F

Temperature ate 5 AM = 51°F

Temperature ate 7 AM = 54°F

Temperature ate 9 AM = 59°F

So, At 3 AM the water is at its lowest temperature.

and

After 10 hours passed, the temperature of the lake is 54°F.

Therefore, Answers are 3 AM ; 10 , 54

7 0
3 years ago
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The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
2 years ago
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