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aalyn [17]
2 years ago
15

Newton and descartes each have 42 glow in the dark stickers newton divides his into 6 equal groups descartes divides his into 7

equal groups who has more stickers in each group
Mathematics
2 answers:
LekaFEV [45]2 years ago
6 0

Newton has more stickers in each group if Newton and Descartes each have 42 glow-in-the-dark stickers newton divides his into 6 equal groups Descartes divides his into 7 equal groups.

<h3>What is a fraction?</h3>

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

It is given that:

Newton and Descartes each have 42 glow-in-the-dark stickers newton divides his into 6 equal groups Descartes divides his into 7 equal groups.

For Newton:

= 42/6

= 7

For Descartes:

= 42/7

= 6

Thus, Newton has more stickers in each group if Newton and Descartes each have 42 glow-in-the-dark stickers newton divides his into 6 equal groups Descartes divides his into 7 equal groups.

Learn more about the fraction here:

brainly.com/question/1301963

#SPJ2

Elodia [21]2 years ago
5 0

Answer:

newton

Step-by-step explanation:

first you have to divide Newtons stickers and get 7, then you divide Descartes stickers and get 6, so therefore Newton has more

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Pre calculus law of sines
lakkis [162]

Answer:

AB = 6.5

Step-by-step explanation:

C = 59°

AC = 7

CD = 6

AB = ?

Apply the Law of Cosines, which is AB² = AC² + CD² - 2(AC)(CD)*Cos(C)

AB² = 7² + 6² - 2(7)(6)*Cos(59)

AB² = 85 - 43.26

AB² = 41.74

AB = √41.74

AB = 6.5 (nearest tenth)

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3 years ago
What is a radius in geometry, and what are some examples of it?
mixer [17]
A radius is a straight line from the centre to the edge of a circle. i’m not sure about any examples sorry :/
6 0
2 years ago
Simplify 4+3(7+4 x 2)-100<br> Solve this
siniylev [52]
4+3(7+4 x 2)-100
4+3(7+8)-100
4+3(15)-100
4+45-100=
-51
8 0
3 years ago
Read 2 more answers
mary has 39 square feet of patio bricks. each square brick has sides 1 foot long. what is the greatest perimeter of a rectangle
bearhunter [10]

-- The smallest perimeter you can make with a certain area
is a circle.

-- The NEXT smallest perimeter with the same area is a square.

   With 1-ft by 1-ft square bricks, the shortest perimeter she could
make would be by using her bricks to make it as square as possible. 
Without cutting bricks into pieces, the best she could do would be  

                           (13 bricks) x (3 bricks) .

                            =    (13-ft) x (3-ft)

           Perimeter = (2 x length) + (2 x width)

                             = (2 x 13-ft)  +  (2 x 3-ft) 
                           
                             =      (26-ft)  +  (6-ft)  =  32 feet  <== shortest perimeter.

-- Then, the more UNSQUARE you make it, the more perimeter
it takes to enclose the same area.  That means Mary has to make
a rectangle as long and skinny as she can.

The longest perimeter she can make (without cutting bricks into
pieces) is    (39 bricks) x (1 brick) .

                        = (39-ft)  x  (1-ft) .

    Perimeter  =  (2 x length) + (2 x width)

                       =   (2 x 39-ft)  +  (2 x 1-ft)

                       =        (78-ft)  +  (2-ft)     =     80 feet .    

What she'll have then is a brick path, 39 feet long and 1 foot wide,
and when you walk on it, you'll need to try hard to avoid falling off
because it's only 1 foot wide.  

7 0
3 years ago
A boat is being pulled into a dock with a rope attached to the boat at water level. When the boat is 12 feet from the dock, the
Natali5045456 [20]

Given :

A boat is being pulled into a dock with a rope attached to the boat at water level. When the boat is 12 feet from the dock, the length of the rope form the boat to the dock is 3 feet longer than twice the height of the dock above the water.

To Find :

The height of the dock.

Solution :

This will make a right angle triangle as given in link below .

Now , applying Pythagoras theorem :

(2h+3)^2=h^2+12^2\\\\4h^2+9h+9=h^2+144\\\\h^2+4h-45=0\\\\(h-5)(h+9)=0

Now , h = 5 or h = -9 .

Now , height cannot be negative .

So , height of the dock is 5 ft .

Hence , this is the required solution .

8 0
3 years ago
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