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harina [27]
3 years ago
8

Given that B is between A and C. If AB=x, BC =2x-3, and AC = 30. Find x and bc

Mathematics
1 answer:
Artemon [7]3 years ago
3 0

Answer:

x=11

BC=19

Step-by-step explanation:

AB+AC=AC this is because B is in between A and C. So now we can substitute all of the line segments, so we have

x+2x-3=30          Now you add 2x and x

3x-3=30      Now you add 3 to both sides so you can get 3x alone on one side

3x=33        Now you divide both sides by 3 so you get the x alone on one side

x=11

The next step is to substitute x to find BC.

BC=2x-3       Substitute the x with 11

BC=2(11)-3    Then multiply 2 and 11 because that is the rule with parenthesis

BC=22-3        then subrtact the 3 from 22

BC=19

You can check your work by doing AB+BC=AC

11+19=30        substitute your answers and then add them together

30=30

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NEED HELP
solmaris [256]

The solutions to the systems of equations are:

1. (2, 3) (see attachment below). [one solution]

2. no solution

3. (3, 13) [one solution]

<h3>Solution to a System of Equations?</h3>

The solution to a system of equations is the x-value and y-value that will make both equations true. It can be found either using a graph, by elimination method, or substitution method as explained below.

1. Using graph to solve y = 2x - 1 and y = 4x - 5:

The solution is the point where both lines intersect which is: (2, 3) (see attachment below). [one solution]

2. Solving using substitution method:

x = -5y + 4 ---> eqn. 1

3x + 15y = -1 ---> eqn. 2

Substitute x = -5y + 4 into eqn. 2

3(-5y + 4) + 15y = -1

-15y + 12 + 15y = -1

-15y + 15y = -1 - 12

0 = -13 (this shows that there is no solution)

3. Using elimination method:

14x = 2y + 16 ---> eqn. 1

5x = y + 2 ---> eqn. 2

1(14x = 2y + 16)

2(5x = y + 2)

14x = 2y + 16 ----> eqn. 3

10x = 2y + 4 -----> eqn. 4

Subtract

4x = 12

x = 12/4

x = 3

Substitute x = 3 into eqn. 2

5(3) = y + 2

15 = y + 2

15 - 2 = y

13 = y

y = 13

The solution is: (3, 13).

Learn more about the solution of a system of equations on:

brainly.com/question/13729904

#SPJ1

5 0
2 years ago
What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4
Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.  

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

I = \frac{P}{4\pi d^{2}}

<em>where P: is the power ans d: is the distance. </em>

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km     </em>

\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}

\frac{I_{1}}{I_{2}} = 5.9:1

Therefore, the ratio of the intensities is roughly 6:1.  

 

I hope it helps you!    

3 0
3 years ago
Combine like terms 6x^2+4(x^2-1)
ki77a [65]
6x^2 + 4(x^2 - 1) = 
6x^2 + 4x^2 - 4 = 
10x^2 - 4 <===
4 0
3 years ago
Read 2 more answers
Riday<br> The x-intercepts of y = 5 (1 + 4) (x - 3)<br> are<br> and<br> NEED HELP ASAP
nikklg [1K]
The answers are -4 and 3 :)
6 0
3 years ago
from a point P the length of the tangent to a circle is 24 cm and the radius is 7 cm find the distance of P from the centre​
Mice21 [21]

Answer:

22.96 cm

Step-by-step explanation:

Let the point of contact of the tangent with the circle be R.

Let the centre of the circle be O.

We are told that from Point P, the length of the tangent is 24 cm.

Thus, PR = 24 cm

Now, the radius will be perpendicular to the tangent at the point of contact with the circle.

Thus, ORP will form a right angle triangle where ∠R = 90°

Since radius = 7 cm, we can use pythagoras theorem to find OP which is the distance of P from the centre.

Thus;

OP = √(24² - 7²)

OP = √527

OP = 22.96 cm

6 0
3 years ago
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