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3 years ago

Greatest common factor for 28y^7x^4u^3 and 8x^4u^5

Mathematics

1 answer:

Nataly [62]3 years ago

3 0

Answer:

Step-by-step explanation:

$28y^{7} *x^{4} *u^{3} \\8x^{4} *u^{5}$

rewrite those 2 terms to better see what they have in common

$4*7 *x^{4} *u^{3} *y^{7} \\4*2*x^{4}*u^{3} *u^{2}$

because, 4*7 =28, 4*2=8, u³*u² =u^5, and multiplication is commutative

The greatest common factor is:

$4x^{4} u^{3}$

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Alenkasestr [34]

Answer:

The domain is t ≥ 0

The range is D ≥ 0

Step-by-step explanation:

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d₀ is the initial position of the train.

We can assume the distance they go is not negative so...

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2 years ago

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beks73 [17]

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Hence the answer is

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1 year ago

Change 2x-y=-4 into slope-intercept form with steps

Art [367]

Answer:

Y=2x+4

Step-by-step explanation:

2x-y=-4

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3 years ago

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Answer:

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3 years ago

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leonid [27]

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