To solve this problem, you can split the shape into a triangle and a parallelogram.
You can do this by imagining/drawing a line from point A to point C>
Now you can work out the area of triangle ACB
1/2 x b x h
1/2 x 5 x 3
= 7.5
Now work out the area of the parallelogram ACDE
b x h
5 x 3 = 15
Add the areas together and then you have the answer
7.5 + 15 = 22.5
Answer:
10 units
Step-by-step explanation:
Given data
P = (3, 1) and Q = (-3, -7)
x1=3
y1=1
x2= -3
y2= -7
The expression for the distance between two coordinate is
d=√((x_2-x_1)²+(y_2-y_1)²)
Substitute
d=√((-3-3)²+(-7-1)²)
d=√((-6)²+(-8)²)
d=√36+64
d=√100
d=10 units
Hence the distance is 10 units
If i am not wrong the question of this woyld be the measure of 1 right . Because both of these are vertical angle so they are equal to each other “><“ like that so measure of 1 is 105 tô
The height is 9.875 feet from which the goalkeeper catches the ball.
The player kicks soccer from a height of 2 feet
x = 0 and y = 2
Maximum height of 20 feet after traveling 40 feet
x = 40, y = 20
So let y = a(x - 40)² + 20 ( the path of parabola)
Since x = 0 , y = 2
So, 2 = a(0 - 40)² + 20
2 = 1600a + 20
-18 = 1600a
a = - 9/800
Thus, y = -9/800(x - 40)² + 20
Since the soccer is caught by the goalkeeper 70 feet from where it was kicked
x = 70
So at this time,
y = -9/800 ( 70 - 40)² + 20
= -9/800 × 900 + 20
= - 81/8 + 20
= 79/ 8
= 9.875 feet
Therefore the height at which the goalkeeper catches the ball is 9.875 feet.
To know more about the height refer to the link given below:
brainly.com/question/27030273
#SPJ1
Answer:
abc to rqp is the right ans
