19.18/2.8= 6.85 hours or rounded it would be 7 hours
Step-by-step explanation:
L = 2W - 8
P = 230 yd
P = 2×(L+W)
230 = 2× (2W - 8 + W)
230 = 2× (3W-8)
230 = 6W-16
6W= 230+16
6W = 246
W = 246/6
W = 41
L = 2(41) -8
= 82-8
= 74
so, the dimensions of the playing field:
the length = 74 yd
the length = 74 ydthe wide = 41 yd
Given that there are 32 girls and 17 boys, the total number of students in the class is 49. In order for us to know the percent of the girls in class, what we are going to do is to simply divide 32 by 49 and then multiply by 100 and the answer is 65.3%. Hope this answers your question.
Answer:
Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.
Step-by-step explanation:
We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.
<u><em>Let </em></u>
<u><em> = sample mean comprehensive strength</em></u>
The z-score probability distribution for sample mean is given by;
Z =
~ N(0,1)
where,
= population mean comprehensive strength = 5500 psi
= standard deviation = 100 psi
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P(
> 4985 psi)
P(
> 4985 psi) = P(
>
) = P(Z > -15.45) = P(Z < 15.45)
= <u>0.99999</u>
<em>Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.</em>