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Complete Question
An arts academy requires there to be 6 teachers for every 132 students and 4 tutors for every 44 students. How many students does the academy have per teacher? Per tutor? How many tutors does the academy need if it has 132 students?
Answer:
a)How many students does the academy have per teacher?
22 students per teacher
b) Per tutor?
11 students per tutor
c) How many tutors does the academy need if it has 132 students?
12 tutors
Step-by-step explanation:
a)How many students does the academy have per teacher?
6 teachers = 132 students
1 teacher = x
6 × x = 132 × 1
x = 132 × 1/6
x = 22 students
Hence, we have 22 students per tutor
b) Per tutor?
4 tutors = 44 students
1 tutor = x students
Cross Multiply
4 × x = 1 × 44
x = 44/4
x = 11 students
Hence, we have 11 students per tutor
c) How many tutors does the academy need if it has 132 students?
44 students = 4 tutors
132 students = x tutors
Cross Multiply
44 × x = 132 × 4
44x = 132 × 4
x = 132 × 4/44
x = 12 tutors
The academy needs 12 tutors if they have 132 students.
Answer:
B'(16,14)
Step-by-step explanation:
In square ABCD, A(2,7) C(8,1) D(2,1). First, find the coordinates of the vertex B. From the attached diagram you can see that CD=6 units and is parallel to the x-axis, AD=6 units and is parallel to the y-axis. So, B(8,7).
The origin O is the center of dilation, 2 is the scale factor. The rule of the dilation is
(x,y)→(2x,2y)
Thus,
B(8,7)→B'(16,14) (see attached figure).
Answer:
the area after 6 years is 3,473 km^2
Step-by-step explanation:
The computation of the area after 6 years is as follows:
= Area × (1 - decreased percentage)^number of years
= 4,800 km^2 × (1 - 5.25%)^6
= 4,800 km^2 × 0.9475^6
= 3,473 km^2
Hence, the area after 6 years is 3,473 km^2
Hello :
<span>√3 = 3^(1/2)
243 = 3^(5)
subsct in :
</span><span>243√3 =3^a
</span> 3^(5)×3^(1/2) = 3^a
3^(5+1/2) = 3^a
a = 5+1/2 = 11/2
a = 5.5
Answer:
4 feet and 2 inches
Step-by-step explanation:
1 foot = 12 inches
x feet = 50 inches
1/12 = x/50 --> 50/12 --> 4 feet and 2 inches