For this case we have the following polynomials:
3x2
x2y + 3xy2 + 1
We have then:
For 3x2:
Classification: polynomial of one variable:
Degree: 2
For x2y + 3xy2 + 1:
Classification: polynomial of two variables
Degree: 2 + 1 = 3
Answer:
The polynomial 3x2 is of one variable with a degree of 2.
The polynomial x2y + 3xy2 + 1 is of two variables a with a degree of 3.
It would be zero bc, 9x-7=-7 you do KCF Change the sign to addition so -7+7=0 now you divide 0 divided by 9=0. Hope this helps
Answer:
an = 4^(n-1)
Step-by-step explanation:
The three given terms have a common ratio of 4:
4/1 = 16/4 = 4
So, this can be described by the function for a geometric sequence:
an = a1×r^(n -1)
where an is the n-th term, a1 is the first term (1) and r is the common ratio (4).
an = 1×4^(n-1)
an = 4^(n -1) . . . . . simplified
12; 4
66; 33.4
32.6
respectively in the blanks
