Option D:
ΔCAN ≅ ΔWNA by SAS congruence rule.
Solution:
Given data:
m∠CNA = m∠WAN and CN = WA
To prove that ΔCAN ≅ ΔWNA:
In ΔCAN and ΔWNA,
CN = WA (given side)
∠CNA = ∠WAN (given angle)
NA = NA (reflexive side)
Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.
Hence option D is the correct answer.
Answer:
Joshua has 2a^2 -6a + 7 more than Maranda.
Step-by-step explanation:
Joshua has 6a^2 -5a + 10 dollars and Maranda has 4a^2 + a + 3 to find out how much more money Joshua has we need to subtract the amount he has by the amount of Maranda's account. Since both expressions are pollynomial we'll have to subtract the numbers wich are multiplying the same power, so we do as follow:
6a^2 - 5a + 10 - (4a^2 + a + 3)
6a^2 - 5a + 10 - 4a^2 -a -3
6a^2 - 4a^2 -5a -a + 10 -3
2a^2 -6a + 7
Joshua has 2a^2 -6a + 7 more than Maranda.
Answer:
Look below
Step-by-step explanation:
Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.
This means triangle BCD is a 30-60-90 (angle measures) right triangle
The proportions of the sides (from smallest to largest) is
x:x√3:2x
We are given that BC = 6 cm. This means...
2x=6
x=3
This means DB is 3 cm and CD is 3√3 cm
Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.
x=3√3
x√3=9
2x=6√3
Now we need to find AB
AB = AD + DB
AB = 9 + 3
AB = 12 cm
To find the average number of customers for dinner, use the simple ratio of 5 lunch customers for every 8 dinner customers.
Because there are 40 lunch customers, this is eight groups of five lunch customers. This means you will need 8 groups of 8 dinner customers to make it equivalent.
8 x 8 = 64
There is an average of 64 customers for dinner.
Answer:
part a is A and E
Step-by-step explanation:
I had token the test
