Answer:
The answer to your question is a = 4.81
Step-by-step explanation:
Process
1.- The angle B and 43° are supplementary
B + 43° = 180°
B = 180 - 43
B = 137°
2.- Calculate angle C
The sum of the internal angles in a triangle equals 180°
A + B + C = 180°
29 + 137 + C = 180
- Solve for C
C = 180 - 29 - 137
C = 14°
3.- Use the law of signs to find a
a / sin A = c / sin C
a / sin 29 = 2.4 / sin 14
- Solve for a
a = 2.4 sin 29 / sin 14
- Simplification
a = 2.4 (0.485) / 0.242
- Result
a = 4.809
So 5^2 -4^2 is 25-16 which is 9
6^2/9 is 36/9 which is 4 +9 is 13
13(13) is 169
Answer:
Explanation:
The problem we are given is
We can write the square root of a fraction as a fraction with a separate radical for the numerator and denominator; this gives us
We can write the whole number 4 as the fraction 4/1; this gives us
We now need to "rationalize the denominator." This means we need to cancel the square root in the denominator. In order to do this, we multiply both numerator and denominator by √(2x); this is because squaring a square root will cancel it:
When multiplying radicals, we can extend the radical over both factors:
Answer:
Step-by-step explanation:
Hello!
The objective of this experiment is to test if the presence of toxaphene in the diet reduces the gain of weight. For these two random samples of female rats were made, one was fed with a diet that contained a low dose of toxaphene and the other, called the control group, was fed with the same type of food but without toxaphene. The weight of the rats was registered in both groups obtaining:
Sample 1 (with toxaphene)
n₁= 19 female rats
S₁= 58g
Sample 2 (control group)
n₂= 21
S₂= 30g
The hypothesis is that the presence of low-dose insecticide in the diet increases the variability in weight gain. Symbolically: σ₁² > σ₂²
The hypothesis is:
H₀: σ₁² ≤ σ₂²
H₁: σ₁² > σ₂²
α: 0.05
This hypothesis test is for the variance ratio, the statistic to use is:
F= (S₁²/S₂²)*( σ₁²/σ₂²)~F
This test is one-tailed (right) and the critical value is:
If F ≥ 2.19, you reject the null hypothesis.
If F < 2.19, you support the null hypothesis.
F= (S₁²/S₂²)*( σ₁²/σ₂²) = (3364/900)*1 = 3.737
Since the calculated value is greater than the critical value, the decision is to reject the null hypothesis. The variability of the weight gain of rats fed with a low dose of insecticide is greater than the variability of the control group.
I hope it helps!
Answer:
The answer is C on Edge or "The ratio given is part to part. The total number of parts in the whole is 1 + 3 = 4."
Step-by-step explanation: