Answer:
Continuous
Step-by-step explanation:
Here we are asked to determine that the data given to us in form of rates of pizza and the toppings is discrete or the continuous.
The discrete data always come in integers where as the continuous data can come in decimals too. For example the number if student in a class is always a discrete data where as the weight of the students in a class is continuous data.
Here we can see that the cost of pizza and the toppings are in decimals. Hence here the data is continuous
Answer:
ikaw mag sagut nyan tiba may utak ka? Tanga kaya mo na yan
Step-by-step explanation:
She's imperfect but she tries
She is good but she lies
She is hard on herself
She is broken and won't ask for help
She is messy but she's kind
She is lonely most of the time
She is all of this mixed up
And baked in a beautiful pie
She is gone but she used to be mine
For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have two points through which the line passes:

We found the slope:

Substituting we have:

Thus, the equation is of the form:

We substitute one of the points and find the cut-off point:

Finally, the equation is:

ANswer:

Answer:
170
Step-by-step explanation:
The given relations can be used to write and solve an equation for the number of stickers Peter has.
<h3>Setup</h3>
Let p represent the number of stickers Peter has. That is twice as many as Joe, so Joe has (p/2) stickers. Joe has 40 more stickers than Emily, so the number of stickers Emily has is (p/2 -40).
The total number of stickers is 300:
p +p/2 +(p/2 -40) = 300
<h3>Solution</h3>
2p = 340 . . . . . . . . . . . . . . add 40, collect terms
p = 170 . . . . . . . . . . . divide by 2
Peter has 170 stickers.
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<em>Additional comment</em>
Joe has 170/2 = 85 stickers. Emily has 85-40 = 45 stickers.
We could write three equations in three unknowns. Solving those using substitution would result in substantially the same equation that we have above. Or, such a system of equations could be solved using a calculator's matrix functions, as in the attachment.
p +j +e = 300
p -2j +0e = 0
0p +j -e = 40