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Sliva [168]
3 years ago
13

The gravitational field on the surface of the earth is stronger than that on the surface of the moon. If a rock is transported f

rom the moon to the earth, which properties of the rock change? The gravitational field on the surface of the earth is stronger than that on the surface of the moon. If a rock is transported from the moon to the earth, which properties of the rock change? mass only weight only both mass and weight neither mass nor weight
Physics
1 answer:
topjm [15]3 years ago
4 0

Answer: Weight only.

Explanation: Mass is a measure of the amount of matter in an object. Weight is a measure of the gravitational force exerted on the material in a gravitational field. Mass and weight are proportional to each other, with the acceleration due to gravity as the proportionality constant.

If a rock is transported from the moon to the earth, the mass is constant for the object but the weight will depends on the locations of the object. The gravitational acceleration would change because the radius and mass of the Moon is different from the Earth.

Thus, the object (rock) has <em>mass, m</em> both on the surface of the Earth and the surface of the Moon; but it will <em>weight</em> much less on the surface of the Moon as the Moon's surface gravity is 1/6 of the Earth.

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vovangra [49]
The maximum magnitude of the net force on the box is 20 N, which is only possible if the boy and the girl pull the box together in the same direction, horizontally and parallel to the ground.
The minimum magnitude of the net force on the box is 0 N, which will occur when the boy and the girl pull the box together in the parallel but opposite direction.
If either of them pulls at an angle from the horizontal, then the magnitude of the net force will be between 0 N and 20 N.
8 0
3 years ago
At NASA's Zero Gravity Research Facility in Cleveland, Ohio, experimental payloads fall freely from rest in an evacuated vertica
Diano4ka-milaya [45]

Answer:

(a). Energy is 64,680 J

(b) velocity is 51.43m/s

(c) velocity in mph is 115.0mph

Explanation:

(a).

The potential energy P of the payload of mass m is at a vertical distance h is  

P =mgh.

Therefore, for the payload of mass m = 50kg at a vertical distance of h = 132 m, the potential energy is

P = (50kg)(9.8m/s^2)(132m)

\boxed{P = 64,680J}

(b).

When the payload reaches the bottom of the shaft, all of its potential energy is converted into its kinetic energy; therefore,

mgh= \dfrac{1}{2}mv^2

v= \sqrt{2gh}

v = \sqrt{2*9.8*135}

\boxed{v = 51.43m/s}

(c).

The velocity in mph is

\dfrac{51.43m}{s} * \dfrac{3600s}{hr} * \dfrac{1mile}{1609.34m}

\boxed{v= 115.0mph}

5 0
3 years ago
A positively charged particle 1 is at the origin of a Cartesian coordinate system, and there are no other charged objects nearby
8090 [49]

Answer:

P=(2 nm, 8mn)

Explanation:

Given :

Position of positively charged particle at origin, O=(0\ nm,0\ nm)

Position of desired magnetic field, D\equiv(1\ nm,8\ nm)

Magnitude of desired magnetic field, E=0\ N.C^{-1}

Let q be the positive charge magnitude placed at origin.

<u>We know the distance between the two Cartesian points is given as:</u>

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

<u>For the electric field effect to be zero at point D we need equal and opposite field at the point.</u>

\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 } =\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 }

\therefore (1-0)^2+(8-0)^2=r^2

r^2=65\ nm

r=\sqrt{65}

as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the  given point.

assuming that the second charge is placed at (x,y) nano-meters.

Therefore,

x=2\times 1=2\ nm

and

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3 0
3 years ago
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You may jump higher because the more the mass of the planet, the more gravitational force. There is less mass(and gravity) on Callisto so you wouldn’t be weighed down as much and can jump higher. Whereas on Jupiter there is more weight holding you down.
3 0
3 years ago
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jeka57 [31]

Answer:

Stationary Front, warm front, cold front, Occluded Front.

Explanation:

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cold front is the leading edge of a cooler mass of air at ground level that replaces a warmer mass of air and lies within a pronounced surface trough of low pressure. It often forms behind an extratropical cyclone (to the west in the Northern Hemisphere, to the east in the Southern), at the leading edge of its cold air advection pattern—known as the cyclone's dry "conveyor belt" flow. Temperature differences across the boundary can exceed 30 °C (86 °F) from one side to the other. When enough moisture is present, rain can occur along the boundary. If there is significant instability along the boundary, a narrow line of thunderstorms can form along the frontal zone. If instability is weak, a broad shield of rain can move in behind the front, and evaporative cooling of the rain can increase the temperature difference across the front. Cold fronts are stronger in the fall and spring transition seasons and weakest during the summer.

A warm front is a density discontinuity located at the leading edge of a homogeneous warm air mass, and is typically located on the equator-facing edge of an isotherm gradient. Warm fronts lie within broader troughs of low pressure than cold fronts, and move more slowly than the cold fronts which usually follow because cold air is denser and less easy to remove from the Earth's surface. This also forces temperature differences across warm fronts to be broader in scale. Clouds ahead of the warm front are mostly stratiform, and rainfall gradually increases as the front approaches. Fog can also occur preceding a warm frontal passage. Clearing and warming is usually rapid after frontal passage. If the warm air mass is unstable, thunderstorms may be embedded among the stratiform clouds ahead of the front, and after frontal passage thundershowers may continue. On weather maps, the surface location of a warm front is marked with a red line of semicircles pointing in the direction of travel.

In meteorology, an occluded front is a weather front formed during the process of cyclogenesis. The classical view of an occluded front is that they are formed when a cold front overtakes a warm front, such that the warm air is separated (occluded) from the cyclone center at the surface. The point where the warm front becomes the occluded front is called the triple point; a new area of low-pressure that develops at this point is called a triple-point low. A more modern view of the formation process suggests that occluded fronts form directly during the wrap-up of the baroclinic zone during cyclogenesis, and then lengthen due to flow deformation and rotation around the cyclone.

3 0
2 years ago
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