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Step2247 [10]
4 years ago
9

Why are collisions between galaxies more likely than collisions between stars within a galaxy?

Physics
1 answer:
KatRina [158]4 years ago
8 0

Answer:

stars share a gravitational force with the galaxy while nearby galaxies do not share a gravitational field.

Explanation:

stars will not collide because they are bound by a gravitational orbit around the galaxy

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A 65 kg cart travels at a constant speed of 4.6 m/s. What is its kinetic energy?
Talja [164]

Answer:

Explanation:

mass (m) = 65 kg

velocity (v) = 4.6 m/s

Kinetic energy (KE)

= 1/2 * m * v²

= 1/2 * 65 * 4.6²

=  687.7 J

hope it helps :)

7 0
3 years ago
The pressure exerted by a phonograph needle on a record is surprisingly large, due to the very small width of the needle. If the
Alex

Answer:

102597.6 Pa

Explanation:

mass, m = 1.25 g

Force, F = m x g = 1.25 x 9.8 x 10^-3 = 0.01225 N

radius, r = 0.195 mm = 0.195 x 10^-3 m

Area, A = πr² = 3.14 x 0.195 x 0.195 x 10^-6 m^2

A = 1.19 x 10^-7 m^2

Pressure is defined as the thrust acting per unit area.

P = Force / Area

P = 0.01225 N / (1.10 x 10^-7)

P = 102597.6 Pa

Thus, the pressure exerted is 102597.6 Pa.

6 0
3 years ago
Which statement accurately describes current electricity?
horsena [70]

Answer:

D. It is caused by flowing negatively charged particles.

Explanation:

Current electricity is caused by flowing negatively charged particles. Current flows in a direction opposite the that of the charged particles.

The negatively charged particles can be electrons or ions in solutions.

As the electrons flows, current is generated in the opposite direction.

 The potential difference is what drives the current and it is dependent on the available energy in the cell.

6 0
3 years ago
Read 2 more answers
A rectangular key was used in a pulley connected to a line shaft with a power of 7.46 kW at a speed of 1200 rpm. If the shearing
Damm [24]

Given:

Shaft Power, P = 7.46 kW = 7460 W

Speed, N = 1200 rpm

Shearing stress of shaft, \tau _{shaft} = 30 MPa

Shearing stress of key, \tau _{key} = 240 MPa

width of key, w = \frac{d}{4}

d is shaft diameter

Solution:

Torque, T = \frac{P}{\omega }

where,

\omega = \frac{2\pi  N}{60}

T = \frac{7460}{\frac{2\pi  (1200 )}{60}} = 59.365 N-m

Now,

\tau _{shaft} = \tau _{max} = \frac{2T}{\pi (\frac{d}{2})^{3}}

30\times 10^{6} = \frac{2\times 59.365}{\pi (\frac{d}{2})^{3}}

d = 0.0216 m

Now,

w =  \frac{d}{4} =  \frac{0.02116}{4} = 5.4 mm

Now, for shear stress in key

\tau _{key} = \frac{F}{wl}

we know that

T = F \times r =  F. \frac{d}{2}

⇒ \tau _{key} = \frac{\frac{T}{\frac{d}{2}}}{wl}

⇒ 240\times 10^{6} = \frac{\frac{59.365}{\frac{0.0216}{2}}}{0.054l}

length of the rectangular key, l = 4.078 mm

7 0
3 years ago
Read 2 more answers
Natalie and Will are discussing socialization. Natalie says that socialization occurs when an animal becomes accustomed to the p
skad [1K]
The correct answer for this question is this one: "C. Neither Natalie nor Will." Natalie and Will are discussing socialization. Natalie says that socialization occurs when an animal becomes accustomed to the people in the household. <span>Will says that socialization is easily attained if the animal is first exposed to humans after 12 weeks of age.</span>
7 0
3 years ago
Read 2 more answers
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