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3 years ago

8

Which of the following means that an image is real?

2 answers:

DochEvi [55]3 years ago

8 0

To declare an image is real you would call it “authentic”

luda_lava [24]3 years ago

8 0

Answer:

what you mean bruh

Explanation:

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What is rectilinear propagation of light?

nignag [31]

Answer:

Rectilinear propagation describes the tendency of electromagnetic waves to travel in a straight line. Light does not deviate when travelling through a homogeneous medium, which has the same refractive index throughout; otherwise, light suffers refraction.

3 0

3 years ago

Read 2 more answers

sergey [27]

Answer:

Grain

Explanation:

I just got it wrong :)

5 0

4 years ago

A student drops a 0.4kg ball from a height a of 49m above the ground. Neglect drag. Answer each of the following questions about

Elan Coil [88]

• The only force acting on the ball, and thus the net force, is due to its own weight, with magnitude

<em>w</em> = <em>m</em> <em>g</em> = (0.4 kg) (9.8 m/s²) ≈ 3.9 N

pointing downward.

• The ball is in free fall, so its acceleration is <em>g</em> = 9.8 m/s² (also pointing downward).

• The ball is dropped from a height of 49 m, so its height <em>y</em> at time <em>t</em> is

<em>y</em> = 49 m - 1/2 <em>g</em> <em>t</em> ²

Set <em>y</em> = 0 and solve for <em>t</em> :

0 = 49 m - 1/2 <em>g t</em> ²

<em>t</em> ² = (98 m) / <em>g</em>

<em>t</em> = √((98 m) / <em>g</em>) = √(10) s ≈ 3.2 s

• The ball's velocity <em>v</em> at time <em>t</em> is

<em>v</em> = - <em>g t</em>

so that at the time found previously, the ball will have attained a velocity of

<em>v</em> = - <em>g</em> (3.2 s) ≈ -31 m/s

and thus a <em>speed</em> of about 31 m/s.

4 0

3 years ago

Find the velocity (in m/s) of a proton that has a momentum of 4.96 X 10^-19 kg.m/s.

kramer

Answer:

The velocity of the proton is $2.965*10^{8} \frac{m}{s}$

Explanation:

The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:

p=m*v Equation (1)

Where:

p: Is the momentum in kg*m/s

m: Is mass of the particle in kg

v: Is the velocity of the particle in m/s

Data known:

m= 1,6726 × 10^–27 kg : mass of the proton

p= 4.96 X 10^-19 kg.m/s.

We replace this data in the Equation (1):

$4,96*10^{-19} =1.6726*10^{-27} *v$ $v=\frac{4.9*10^{-19} }{1.6726*10^{-27} }$

$v=(\frac{4.96}{1.6726} )*(10^{27-19} )$

$v=2,965*10^{8} m/s$

Answer: The velocity of the proton is $2.965*10^{8} \frac{m}{s}$

3 0

3 years ago

An object is in circular motion. How will the object behave if the centripetal force is removed

stich3 [128]

The object will sail away in a straight line ... continuing in the same direction it was going when the centripetal force stopped.

3 0

3 years ago