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3 years ago

Evaluate. Show all work 51-(21-5)x2

Mathematics

2 answers:

marishachu [46]3 years ago

8 0

Step-by-step explanation:

B bracket

O of

D division

M multiplication

A addition

S subtraction

therefore 51-32 is equal to 49

masya89 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

51-(16)x2

16x2=32

51-32=19

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The volume of the prism is 900 cubic centimeters. The height is 15 cm and the height of the triangular base is 10 cm. What is th

gulaghasi [49]

Answer:

the length of FC = b = 12 cm

Step-by-step explanation:

The volume of prism is given along with height and height of triangular base. WE need to find the length of base.

V= B*h

where B= area of base = 1/2 * b *h

V= ( 1/2 *b * h) * h

900= 1/2 * b * 10 * 15

900 * 2 = b* 150

1800 = b* 150

=> b= 1800/150

b= 12 cm

So the length of FC = b = 12 cm

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4 years ago

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If the volume of a cube is 245cm^3 what is the length of one side?

vova2212 [387]

Answer:

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Step-by-step explanation:

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3 years ago

Please help, i’ll give brainiest answer :) [Image]

anygoal [31]

Answer: 20

Step-by-step explanation:

Step 1: Find the vertices (intersections) of the constraints by either graphing or solving the system of equations. I graphed them and found two of the vertices: (0, 1) and (4,0) but needed to solve the system to find the third vertex (point of intersection).

-x + 3 = $\frac{1}{3}x$ + 1

+x -1 +x -1

2 = $\frac{4}{3}x$

(3)2 = $(3)\frac{4}{3}x$

6 = 4x

÷4 ÷4

$\frac{3}{2}$ = x

y = $\frac{1}{3}x$ + 1

= $\frac{1}{3}(\frac{3}{2)}$ + 1

= $\frac{1}{2}$ + 1

= $\frac{3}{2}x$

Third vertex is at $(\frac{3}{2},\frac{3}{2)}$

Step 2: Input the vertices into the objective function: C = 5x - 4y

(0, 1): C = 5(0) - 4(1)

= 0 - 4

= -4

$(\frac{3}{2},\frac{3}{2)}$ : C = 5 $(\frac{3}{2})$ - 4 $(\frac{3}{2})$

= $\frac{15}{2}$ - $\frac{12}{2}$

= $\frac{3}{2}$

= 1.5

(4, 0): C = 5(4) - 4(0)

= 20 - 0

= 20

Step 3: Evaluate the answers above to find the maximum: 20

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3 years ago

Let(Gn)n=1,be a geometric progression if Gk +G(k+1)=a and G(k+1) +G(k+2)=b,then find r and Gk

kirill [66]

At least to the power or not progression 278347

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3 years ago

The coordinates of the vertices of quadrilateral ABCD are A(0, −4) , B(−4, 3) , C(3, 4) , and D(6, −1) . Drag and drop the choic

Art [367]

Answer:

The slope of AB is -7/4, the slope of BC is 1/7 , the slope of CD is 5/3, and the slope of AD is 2. So, Quadrilateral ABCD is neither a parallelogram nor a trapezoid because neither pair of opposite sides are parallel.

Step-by-step explanation:

Since, a quadrilateral having,

One pair of parallel opposite sides is Trapezoid,

While, having two pair of parallel opposite sides is parallelogram.

Since, the slope of a line segment having the end points $(x_1, y_1)$ and $(x_2, y_2)$ is,