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2 years ago

Evaluate. Show all work 51-(21-5)x2

Mathematics

2 answers:

marishachu [46]2 years ago

8 0

Step-by-step explanation:

B bracket

O of

D division

M multiplication

A addition

S subtraction

therefore 51-32 is equal to 49

masya89 [10]2 years ago

5 0

Answer:

Step-by-step explanation:

51-(16)x2

16x2=32

51-32=19

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sleet_krkn [62]

C. multiply because of the order of operations

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3 years ago

#Quality answer needed #No spam _/|\_

Rina8888 [55]

Answer:

Step-by-step explanation:

Given,

Cost price of the car when Arjun bought = ₹ 3,50,000

Cost price of that same car after 1 year = ₹ 3,70,000

So,

Amount of money increased on the car's price

= ₹ (3,70,000 - 3,50,000)

= ₹ 20,000

Therefore, 

Percentage of increase on the car's price

$= \frac{20000}{350000} \times 100$

[On Simplification]

$= \frac{2}{35} \times 100$

[On further Simplification]

= 5.7142......

= 5.71 (approx.)

Hence,

Percentage in increase of car's price was 5.71% (Ans)

7 0

2 years ago

Read 2 more answers

Show the work of 6.2 +3.4

Musya8 [376]

Answer:

9.6

Step-by-step explanation:

When we are adding decimals we try 2 add them like normal integers, but in the end we add the decimal in the same place as it was in the beginning

so 62+34=96 and there's a decimal in the tenths place so its 9.6

8 0

3 years ago

What is the 7th term of the geometric sequence 4, -20, 100

Sloan [31]

1st let's calculate r the common ratio:
r = (-20)/4 = (100/-20) = -5

Value of nth term = a₁.rⁿ⁻¹, where a₁= 1st term and n, the rank

Value of nth term = 4r⁽⁷⁻¹⁾ = 4.(-5)⁶

Value of nth term = 62,500

4 0

3 years ago

A student scores 73 out of 100 on a test. If the maximum score on the next test is also 100 points, what score does the student

vesna_86 [32]

Because the student scored 73/100 on the first test, their current average is 73%.

To calculate the avergae with the next test score, you add both percentages the student gets together and then divide by 2.

79 = (73 + x) / 2

Multiply by 2 on both sides

158 = 73 + x

Subtract 73 on both sides

x = 85

So the student needs to get at least an 85/100 on the next test to maintain a 79 average.

3 0

3 years ago