All categories

3 years ago

7. Convert 158 g of C to moles.

Chemistry

1 answer:

LuckyWell [14K]3 years ago

3 0

Answer:

Number of mole = 13.155moles

Explanation:

One mole of a substance is equal to 6.022 * 10^23 units of that substance.

Mole of a substance can be defined according to chemistry as the mass of substance containing the same number of fundamental units

Using the formula for mole

n = m/Mm

n = number of mole

m = number of mass

Mm = number of molar mass

We are provided with some information

Given: mass of carbon to be 158g

Molar mass of C = 12.0107g/mol

Using the formula

n = m/Mm

n = 158 / 12.0107

n = 13.155 moles

You might be interested in

A 0.750-g sample of a compound that might be iron(II) chloride, nickel(II) chloride, or zinc chloride is dissolved in water, and

DedPeter [7]

Answer: The compound is nickel (II) chloride.

NiCl2

Explanation:

Let's assume that the compound is X.

Then,

XCl2 + 2AgNO3 ---> X(NO3)2 + 2AgCl

Given,

Volume of AgNO3 = 22.4ml = 0.0224L

Concentration of AgNO3 = 0.515M

no of moles = concentration x volume

:• n(AgNO3) = 0.515 x 0.0224

n(AgNO3) = 0.011536 mol

Therefore, no of moles of AgNO3 is 0.0011536mol

From the equation above, we can deduce that;

n(XCl2) = 1/2n(AgNO3)

:• n(XCl2) = 1/2 × 0.011536

n(XCl2) = 0.005768

Therefore number of moles of XCl2 is 0.005768 mol.

Mass, m, of XCl2 = 0.75g (Given)

Molar mass = mass/ no of moles

Molar mass of XCl2 = 0.75/0.005768

:• molar mass of XCl2= 130.03g/mol

Molar mass of Cl = 35.453

Cl2= 2 x 35.453 = 70.906

Molar mass of XCl2 = M.mass of X +

M.mass of Cl2

:• 130.03 = M.mass of X + 70.906

Molar mass of X = 130.03 - 70.906

Molar mass of X = 59.1

By comparing to literature, we can conclude that X is Nickle ,Ni.

Therefore, the compound is NiCl2 , Nickle(II) Chloride.

4 0

3 years ago

In which form is most of the water on Earth? A. solid B. gas and solid C. liquid D. gas

kotykmax [81]

C. Liquid. The Earth is mostly water, namely ocean water which is liquid.

4 0

4 years ago

Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq) , as described b

Katyanochek1 [597]

Answer:

$m_{MnO_2}=1.378gMnO_2$

Explanation:

Hello,

In this case, we first apply the ideal gas equation to compute the moles of produced chlorine:

$n_{Cl_2}=\frac{PV}{RT}=\frac{765 Torr*\frac{1atm}{760Torr}*0.385L}{0.082\frac{atm*L}{mol*K}*298.15K} =0.01585molCl_2$

Then, by considering the given reaction, applying the stoichiometry, that shows a 1 to 1 relationship between chlorine and manganese dioxide, we find:

$m_{MnO_2}=0.01585molCl_2*\frac{1molMnO_2}{1molCl_2} *\frac{86.937gMnO_2}{1molMnO_2} \\m_{MnO_2}=1.378gMnO_2$

Best regards.

3 0

3 years ago

3 points

melamori03 [73]

D) The same number of each type of atom will always be present before and after a chemical reaction takes place.

Mass is never created or lost in a chemical reaction, so the atoms of each element must stay balanced.

8 0

3 years ago

Oxalic+acid+is+a+toxic+substance+used+by+laundries+to+remove+rust+stains.+its+composition+is+26.7%+c,+2.2%+h,+and+71.1%+o+(by+ma

Anettt [7]

The molecular formula of a compound is C₂H₂O₄.

Take 100 grams of compound:

1) ω(C) = 26.7% ÷ 100% = 0.267

m(C) = ω(C) × m(compound)

m(C) = 0.267 × 100 g.

m(C) = 26.7 g.

n(C) = m(C) ÷ M(C).

n(C) = 26.7 g ÷ 12 g/mol.

n(C) = 2.22 mol; amount of carbon

2) ω(H) = 2.2 % ÷ 100% = 0.022

m(H) = 0.022 × 100 g.

m(H) = 2.2 g.

n(H) = 2.2 g ÷ 1 g/mol.

n(H) = 2.2 mol; amount of hydrogen

3) ω(O) = 71.1 % ÷ 100%.

ω(O) = 0.711

m(O) = 0.711 × 100 g

m(O) = 71.1 g

n(O) = 71.1 g ÷ 16 g/mol

n(O) = 4.4 mol; amount of oxygen

4) n(C) : n(H) : n(O) = 2.2 mol : 2.2 mol : 4.4 mol /2.2 mol.

n(C) : n(H) : n(O) = 1 : 1 : 2

M(CHO₂) = 45 amu; empirical formula

90 amu ÷ 45 amu = 2 CHO₂

More info about empirical formula: brainly.com/question/1873039

#SPJ4

5 0

1 year ago

7. Convert 158 g of C to moles.​

7. Convert 158 g of C to moles.