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astraxan [27]
3 years ago
11

HCN H:C:N: 3. Is this Lewis Structure correct?

Chemistry
1 answer:
Naddika [18.5K]3 years ago
6 0

Answer:

No, your missing some bonds

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Typically, alkali metals tend to have
vladimir2022 [97]

Answer:

d

Explanation:

hmmmmmmmmmmmmmmmm

5 0
3 years ago
What are isoelctronic species​
BARSIC [14]

Species that have the same number of electrons or the same electronic structure.

6 0
3 years ago
Suppose 0.708g of copper(II) acetate is dissolved in 50.mL of a 46.0mM aqueous solution of sodium chromate.
lisabon 2012 [21]

Answer:

The final molarity of acetate anion in the solution is 0.0046 moles

Explanation:

The balanced equation is

Cu(C₂H₃O₂)₂ + Na₂CrO₄ = CuCrO₄ + 2Na(C₂H₃O₂)

Therefore one mole of Cu(C₂H₃O₂)₂ react with one mole of Na₂CrO₄ to form one mole of CuCrO₄ and two moles of Na(C₂H₃O₂)

Mass of copper (II) acetate present = 0.708 g

Volume of aqueous sodium present = 50 mL

Molarity of sodium chromate = 46.0 mM

Therefore

Number of moles of sodium chromate present = (50 mL/1000)×46/1000 = 0.0023 M

Number of moles of copper (II) acetate present = 181.63 g/mol

number of moles of copper (II) acetate present = (0.708 g/181.63 g/mol) =0.0039 moles

Therefore 0.0039 moles of Cu(C₂H₃O₂)₂ × (2 moles of Na(C₂H₃O₂))/1 Cu(C₂H₃O₂)₂) = 0.00779 moles of Na(C₂H₃O₂)

also 0.0023 moles of Na₂CrO₄ × (2 moles of Na(C₂H₃O₂))/1 Na₂CrO₄) = 0.0046 moles of Na(C₂H₃O₂)

Therefore the Na₂CrO₄ is the limiting reactant and 0.0046 moles of Na(C₂H₃O₂) or acetate anion is formed

7 0
3 years ago
If 10.5-g of Na2SO4 are actually recovered experimentally, that is the percent yield?
SVEN [57.7K]
<span>"If they recover 10.5 it means you shall add with the limiting 10.8, giving you 21.3g out of 142 times 100, giving 15%, I believe."
By anonymous on openstudy.com

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5 0
3 years ago
What is a Brønsted-Lowry acid?
Luden [163]

Answer:

La teoría de Brønsted-Lowry es una teoría sobre las reacciones ácido-base que fue propuesta independientemente por Johannes Nicolaus Brønsted y Thomas Martin Lowry en 1923.

3 0
3 years ago
Read 2 more answers
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