Answer: A reversible reaction is a reaction that takes place in back and front directions. If the reaction were to reach equilibrium, the rate of forward direction would be equal to that of the reverse reaction.
Explanation:
Reversible reactions :
These are the reaction in which reactants reacts to give product and products reacts to give reactants as a product in return.
- In above equation, 'A' and 'B' are reacting together to give 'C' and 'D', as products and vice-versa.
- When the above reaction reaches equilibrium the rate of forward and backward reaction becomes equal.
<h3>
Answer:</h3>
2.999 mol Br
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
1.806 × 10²⁴ molecules Br
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
<u />
= 2.999 mol Br
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
Our final answer is already in 4 sig figs, so there is no need to round.
Answer :
The complete equation for the reaction of sulfuric acid and sugar is,
By the stoichiometry of the reaction,
1 mole of sucrose react with the 11 moles of sulfuric acid to give 12 moles of carbon and 11 moles of water.
In this reaction, sulfuric acid react with sucrose (sugar). It dehydrates the sugar molecules which means it eliminates the water.
Is what? It depends on what your talking about.
Explanation:
The given data for case (1) is as follows.
h = 20 cm = 0.2 m
Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.
Q = 
where, A = area
L = length
k = thermal conductivity = 0.8 W/m
= change in temperature.
Therefore, putting the given values into the above formula as follows.
Q =
= 
= 168 W
For case (2), h = 180 cm = 1.8 m
Therefore, heat lost will be calculated as follows.
Q =
= 
= 18.67 W
Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.
