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netineya [11]
3 years ago
15

A chemist dissolves 0.9 g of an unknown monoprotic (one acidic H) acid in water. She finds that 14.6 mL of 0.426 M NaOH are requ

ired to neutralize the acid.
Chemistry
1 answer:
eduard3 years ago
6 0

Answer:

144.7 g/mol would be the molar mass of the monoprotic acid

Explanation:

We can find the molar mass of the monoprotic acid from the data showed in the excersie. As every titration we can say that:

mEq acid = mEq base

mEq acid = 14.6 mL . 0.426 M

mEq acid = 6.2196 mEq

mEq = Volume (mL) . N = mass (g) / (EQ / 1000), where the EQ is the:

Molar weight / valence. For this case, as the acid is a monoprotic one, we assume Molar Weight = EQ

6.2196 mEq = 0.9 g / (EQ / 1000)

6.2196 mEq . EQ/1000 = 0.9 g

EQ = 0.9 g / 6.2196×10⁻³ = 144.7 g/mol

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The answer is they follow a patter for valence electrons.
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Which of the following substances is most likely to be a liquid at room temperature?
FromTheMoon [43]

The answer is: hydrogen peroxide, H2O2.

H₂O₂(hydrogen peroxide) is pale blue, clear, inorganic liquid.

It is liquid because hydrogen bonds between molecules.

Hydrogen bond is an electrostatic attraction between two polar groups that occurs when a hydrogen atom (H), covalently bound to a highly electronegative atom such as flourine (F), oxygen (O) and nitrogen (N) atoms.

Because of hydrogen bonds, hydrogen peroxide has higher melting and boiling temperatures than other molecules.

8 0
3 years ago
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The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in
olya-2409 [2.1K]

Answer:

2: Moved faster and spread farther apart.

Explanation:

Restate the question: The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in the liquid.

1. moved slower and closer together.

2.moved faster and spread farther apart.

3. contracted in size when heated.

4. expanded in size when heated.

Water that is cold does not have the energy to bounce of the walls, instead it is like a group of animals they group together for the warmth of the others when it gets really cold.

So it cant be 1.

We all know that power lines sag lower on a hot day (or a tire for a car, it has increases pressure). but those are different types of molecules.

So that rules out 3 and 4.

Which leaves you with 2.

The increase in temperature causes the water molecule to gain energy and move quickly, which resulted in water molecule that are farther apart and an increase in water volume.

Hope it helps!

7 0
2 years ago
Read 2 more answers
Help!!
anyanavicka [17]

I believe this a PV = nRT question whereas

you re write the formula and solve for volume

V = nRT/ P

then you input the values

P= pressure constant

V= x

n = moles = 0.2540

R = gas constant should be 8.314J mol

T = C degrees + 273.15 = K

solve for voume

make sure all units match

and use sig figs!!!!

7 0
3 years ago
Calculate the mass, in grams, of Ag2CrO4 that will precipitate when 50.0mL of 0.20M AgNO3 solution is mixed with 40.0mL of 0.10M
Darina [25.2K]

Answer:

1.327 g Ag₂CrO₄

Explanation:

The reaction that takes place is:

  • 2AgNO₃(aq) + K₂CrO₄(aq)  → Ag₂CrO₄(s) + 2KNO₃(aq)

First we need to <em>identify the limiting reactant</em>:

We have:

  • 0.20 M * 50.0 mL = 10 mmol of AgNO₃
  • 0.10 M * 40.0 mL = 4 mmol of K₂CrO₄

If 4 mmol of K₂CrO₄ were to react completely, it would require (4*2) 8 mmol of AgNO₃. There's more than 8 mmol of AgNO₃ so AgNO₃ is the excess reactant. <em><u>That makes K₂CrO₄ the limiting reactant</u></em>.

Now we <u>calculate the mass of Ag₂CrO₄ formed</u>, using the <em>limiting reactant</em>:

  • 4 mmol K₂CrO₄ * \frac{1mmolAg_2CrO_4}{1mmolK_2CrO_4} *\frac{331.73mg}{1mmolAg_2CrO_4} = 1326.92 mg Ag₂CrO₄
  • 1326.92 mg / 1000 = 1.327 g Ag₂CrO₄
7 0
3 years ago
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