Answer:
144.7 g/mol would be the molar mass of the monoprotic acid
Explanation:
We can find the molar mass of the monoprotic acid from the data showed in the excersie. As every titration we can say that:
mEq acid = mEq base
mEq acid = 14.6 mL . 0.426 M
mEq acid = 6.2196 mEq
mEq = Volume (mL) . N = mass (g) / (EQ / 1000), where the EQ is the:
Molar weight / valence. For this case, as the acid is a monoprotic one, we assume Molar Weight = EQ
6.2196 mEq = 0.9 g / (EQ / 1000)
6.2196 mEq . EQ/1000 = 0.9 g
EQ = 0.9 g / 6.2196×10⁻³ = 144.7 g/mol
