Answer:
Equation 2, because Fe is being more reactive, replaces Cu from CuSO₄.
Explanation:
- Equation 1 is: <em>CuSO₄ + 2NaOH → Na₂SO₄ + Cu(OH)₂.</em>
The reaction between CuSO₄ and NaOH will give Na₂SO₄ and Cu(OH)₂ which is a precipitate "replacement reaction".
- While, equation 2 is: <em>CuSO₄ + Fe → Cu + FeSO₄.</em>
The reaction between CuSO₄ and Fe will produce Cu and FeSO₄.
Thus, it is used to extract Cu because Fe is more reactive than Cu, so it can replace it in its salts and Cu can be extracted.
- <em>So, the right choice is: Equation 2, because Fe is being more reactive, replaces Cu from CuSO₄.</em>
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Answer :
1.80 x 10^-4 moles/liter OH-
Explanation:
pH = 3.58 ; [H3O+] = 10^-3.58 = 2.63 x 10^-4 moles/liter
pH = 4.08 ; [H3O+] = 10^-4.08 = 8.32 x 10^-5 moles/liter
One needs to remove:
2.63 x 10^-4 moles/liter – 8.32 x 10^-5 = 1.80 x 10^-4 moles H3O+/liter
According to the equation: H3O+ + OH-=⇒ 2H2O
Moles/ liter of OH- needed:
1.80 x 10^-4 moles H3O+/liter x 1 mole OH-/1mole H3O+ = 1.80 x 10^-4 moles/liter OH-
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Answer:
Information is insufficient,for predicting the boiling point of this solution.