Add all weighs together
calculate carbons weigh
(carb weigh/total)×100
Answer:
He has two protons
Li electron has one electron in its outermost orbital.
Number of neutrons of nitrogen = seven neutrons
The second shell of boron: 3 electrons.
Explanation:
An atom is composed of electrons, protons and neutrons. The number of neutrons is determined by subtraction of the atomic number from the mass number.
The electronic configuration is already known for each of atoms in these questions according to standard tables.
Answer:
50mL of 4M NaCl, 80mL of 40% glucose, 20mL of 1M Tris-HCl (pH 8.5) and 250mL of water.
Explanation:
To make 400mL containing 0.5M NaCl you need to add:
4M / 0.5M = 8 (dilution 1/8). 400mL / 8 = <em>50 mL of 4M NaCl.</em>
Glucose 8% you need to add:
40% / 8% = 5 (dilution 1/5). 400mL / 5 = <em>80 mL of 40% glucose </em>
Buffer 50mM you need to add:
1000mM / 50mM = 20 (dilution 1/20). 400mL / 20 = <em>20mL of 1M Tris-HCl (pH 8.5)</em>
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The resting volume: 400mL - 50mL of 4M NaCl - 80mL of 40% glucose - 20mL of 1M Tris-HCl (pH 8.5) = 250 mL must be completed with water.
Thus, to make the solution you need: <em>50mL of 4M NaCl, 80mL of 40% glucose, 20mL of 1M Tris-HCl (pH 8.5) and 250mL of water.</em>
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I hope it helps!
Answer:
177.3kg C₂₁H₄₄
Explanation:
Based on the chemical reaction:
C₂₁H₄₄ → 3C₂H₄ + C₁₅H₃₂
<em>Where 1 mole of C₂₁H₄₄ produce 3 moles of ethene, C₂H₄.</em>
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To solve this question we need to determine the moles of ethene in 50.4kg. 1/3 these moles are the moles of C₂₁H₄₄ that must be added:
<em>Moles Ethene -Molar mass: 28.05g/mol-</em>
50.4kg = 50400g * (1mol / 28.05g) = 1796.8 moles of ethene
<em>Moles C₂₁H₄₄:</em>
1796.8 moles of ethene * (1 mol C₂₁H₄₄ / 3 mol C₂H₄) = 589.93 moles C₂₁H₄₄
<em>Mass C₂₁H₄₄:</em>
589.93 moles C₂₁H₄₄ * (296g / mol) = 177283g =
<h3>177.3kg C₂₁H₄₄</h3>
