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2 years ago

What are the TWO characteristics of an effective collision?

Chemistry

1 answer:

Montano1993 [528]2 years ago

5 0

Answer:

the TWO characteristics of an effective collision are:

1.Molecules collide with sufficient energy

2.Molecules collide with the proper orientation.

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Two gases are placed in a sealed flask and allowed to react. Which statement is true about the concentrations of the reactants a

3241004551 [841]

The correct answer is they will not necessarily be equal, but they will be constant. The change between reactants and products will be going continuously but the concentration is constant.

7 0

3 years ago

Read 2 more answers

How many lone pairs of electrons are on the central carbon atom in a Lewis Structure of CHI3?

Alborosie

There are zero lone pairs of electrons on the central carbon atom in a Lewis Structure of CHI3. The correct option is b.

Explanation:

Lone pair electrons are those valence electrons of an atom which do not take part in bonding or left after the bonds are formed.

CH $I_{3}$

carbon is the central atom in the compound having 4 valence electrons.

Each iodine molecule has 7 valence electrons.

H has 1 valence electron.

from the Lewis structure of CH $I_{3}$ , it is seen that all four valence electrons of the carbon is involved in bonding with 3 atoms of iodine and 1 atom of hydrogen.

Thus when all valence electrons are involved in bonding no lone pair of electron is found in CH $I_{3}$ that means zero lone pairs of electrons.

The octet of the iodine, carbon and hydrogen gets completed to form the compound.

5 0

3 years ago

Which of the following would increase friction?

KiRa [710]

B. Sand.

Sand would definitely increase friction because of the roughness of it surface. When its surface comes with another rough surface it would tend to increase friction. All other options given tend to reduce friction one way or the other.

5 0

2 years ago

How many grams of precipitate will be formed when 20.5 mL of 0.800 M

Anton [14]

Answer:

There will be formed 1.84 grams of precipitate (NaNO3)

Explanation:

Step 1: The balanced equation

CO(NO3)2 (aq) + 2 NaOH (aq) → CO(OH)2 (s) + 2 NaNO3 (aq)

Step 2: Data given

Volume of 0.800 M CO(NO3)2 = 20.5 mL = 0.0205 L

Volume of 0.800 M NaOH = 27.0 mL = 0.027 L

Molar mass of NaNO3 = 84.99 g/mol

Step 3: Calculate moles of CO(NO3)2

Moles CO(NO3)2 = Molarity * volume

Moles CO(NO3)2 = 0.800 M * 0.0205

Moles CO(NO3)2 = 0.0164 moles

Step 4: Calculate moles NaOH

moles of NaOH = 0.800 M * 0.027 L

moles NaOH = 0.0216 moles

Step 5: Calculate limiting reactant

For 1 mole CO(NO3)2 consumed, we need 2 moles of NaOH to produce 1 mole of CO(OH)2 and 2 moles of NaNO3

NaOH is the limiting reactant. It will completely be consumed.

CO(NO3)2 is in excess. There willbe 0.0216 / 2 = 0.0108 moles of CO(NO3)2 consumed. There will remain 0.0164 - 0.0108 = 0.0056 moles of CO(OH)2

Step 6: Calculate moles of NaNO3

For 2 moles of NaOH consumed, we have 2 moles of NaNO3

For 0.0216 moles of NaOH, we have 0.0216 moles of NaNO3

Step 7: Calculate mass of NaNO3

mass of NaNO3 = moles of NaNO3 * Molar mass of NaNO3

mass of NaNO3 = 0.0216 moles * 84.99 g/mol = 1.84 grams

There will be formed 1.84 grams of precipitate (NaNO3)

5 0

2 years ago

blondinia [14]

Answer:

Helium has melting point of - 272.2°C or - 458°F

Sodium (Na) = 650°C. or 208°C

Magnesium (Mg) = 97.79°C. Or 1202°F

Explanation:

4 0

3 years ago