Answer:
1. The dye that absorbs at 530 nm.
Explanation:
The dye will absorb light to promote the transition of an electron from the HOMO to the LUMO orbital.
The higher the gap, the higher the energy of transition. The energy can be calculated by E = hc/λ, in which h and c are constants and λ is the wavelength.
The equation shows that the higher the energy, the higher the gap and the lower the wavelength.
Therefore, the dye with absorption at 530 nm has the higher HOMO-LUMO gap.
Answer:
31395 J
Explanation:
Given data:
mass of water = 150 g
Initial temperature = 25 °C
Final temperature = 75 °C
Energy absorbed = ?
Solution:
Formula:
q = m . c . ΔT
we know that specific heat of water is 4.186 J/g.°C
ΔT = final temperature - initial temperature
ΔT = 75 °C - 25 °C
ΔT = 50 °C
now we will put the values in formula
q = m . c . ΔT
q = 150 g × 4.186 J/g.°C × 50 °C
q = 31395 J
so, 150 g of water need to absorb 31395 J of energy to raise the temperature from 25°C to 75 °C .
After the body digest your proteins, they will become your amino acid
Answer:
About 277 Kelvin
Explanation:
Take the celcius, and add 273.15 to it
4°C + 273.15 = <u>277.15K</u>
And round the answer to the nearest whole
277.15K ≈ 277K
Answer:
Mass = 36.4 ×10⁻³ g
Explanation:
Given data:
Volume of container = 100 mL ( 100/1000 = 0.1 L)
Pressure = 688 mmHg (0.9 atm)
Temperature = 565°C ( 565 + 273 = 838 K)
Mass in grams of nitrogen = ?
Solution:
According to ideal gas equation,
PV = nRT
n = number of moles
P = pressure
R = general gas constant
T = temperature
From this equation we will determine the number of moles and then we we will calculate the mass.
n = PV/RT
n = 0.9 atm × 0.1 L / 0.0821 atm. L / mol.K × 838 K
n = 0.09 / 68.8
n = 0.0013 mol
or
n = 1.3×10⁻³ mol
Mass of nitrogen gas:
Mass = number of moles × molar mass
Mass = 1.3×10⁻³ mol × 28 g/mol
Mass = 36.4 ×10⁻³ g