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3 years ago

HELPPPP ASAPP!!!!!

Mathematics

1 answer:

Alexxandr [17]3 years ago

4 0

Answer:

96 ft^3 is the volume of the cone

Step-by-step explanation:

h = 8 ft , r = 6 ft

V = 1/3 X r^2 X h

V = 1/3 X (6)^2 X 8

V = 1/3 X 36 X 8

V = 96 ft^3

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You are seeking to be emancipated from your parents. You are looking for an apartment. There are two final choices. Apartment A

Sliva [168]

Answer:

20 months

Step-by-step explanation:

Initial difference = 500$

Monthly difference = 25$

500 / 25 = 20

4 0

3 years ago

A triangle with three acute angles and two congruent sides. Classify the triangle

Rus_ich [418]

Answer:

The triangle has three acute angles, so it is an acute triangle. The triangle has two congruent sides, so, it is an isosceles triangle. It is an acute isosceles triangle.

Step-by-step explanation:

6 0

3 years ago

Can someone please help me with my math question!!

Lena [83]

Answer:

x(12x^2+18x)

Step-by-step explanation:

x(12x^2+18x)=12x^(3)+18x^2

5 0

3 years ago

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

4 years ago

2/17+3/7(3x−5)=−4 What is the solution?

Zanzabum

2/17 + 3/7(3x - 5) = -4
2/17 + 9/7x - 15/7 = -4...multiply by LCD of 119 to get rid of fractions
14 + 153x - 255 = - 476
-241 + 153x = -476
153x = -476 + 241
153x = - 235
x = -235/153

8 0

3 years ago