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3 years ago

How to solve 4x-3y=22,2x-y=10

2 answers:

katrin2010 [14]3 years ago

8 0

4x-3y=22---->(×1): 4x-3y=22
2x-y=10 ---->(× -2): -4x+2y=-20
_________(+)
0-y=2
y=-2
we replace the value of y in one of the eq
4x-3y=22
4x-3×(-2)=22
4x+6=22
4x=16
x=4
so x=4 and y=-2

Lady bird [3.3K]3 years ago

4 0

Is that considered two equations?

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You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl

gtnhenbr [62]

Answer:

maximum difference of radii = $(r-R)=\frac{1}{2\pi ^{2}}$

Step-by-step explanation:

We know that area of circle is given by

$A=\pi \times (radius)^{2}$

For circle with radius 'r' we have

$A_{1}=\pi \times (r)^{2}$

For circle with radius 'R' we have

$A_{2}=\pi \times (R)^{2}$

Now according to given condition we have

$A_{1}-A_{2}\leq \frac{5}{\pi }$

$\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}$

Thus maximum difference of radii = $(r-R)=\frac{1}{2\pi ^{2}}$

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4 years ago

1. Write an equation for two numbers that are 3 units away from 0?

IrinaVladis [17]

Answer:

|3| and |-3|

Step-by-step explanation:

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3 years ago

2. Candles normally cost £6 each.

saw5 [17]

Answer: candies are us has a better offer

Step-by-step explanation:

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3 years ago

Find the difference 4 2/5 minus 1 7/10

aev [14]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the local maximum value of the function? (Round answer to the nearest thousandth)

natima [27]

Answer:

72.578 to the nearest thousandth.

Step-by-step explanation:

g(x)=3x^3 + 3x^2 - 30x + 24

Find the derivative:

g'(x) = 9x^2 + 6x - 30.

This equals zero for values of turning points:

9x^2 + 6x -30 = 0

3(3x^2 + 2x - 10) = 0

x = [-(2) +/- √(2^2 - 4*3*-10)] / 2*3

x = (-2 +/- √124) / 6

x = (-2 + 11.136)/6, (-2 - 11.136)/6

x = 1.523, -2.189.

To check which value of x gives a maximum value for f(x) use the second derivative test:

g"(x) = 18x + 6

when x = -2.189 g"(x) = 18(-2.189) + 2 which is negative so this value gives a local maximum.

Local maximum value for f(x)

= 3(-2.189)^3 + 3(-2.189)^2 - 30(-2.189) + 24

= 72.578 answer.

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3 years ago