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professor190 [17]

2 years ago

6

At an airport , it costs $7 to park for up to one hour and $5 per hour for each additional hour. Let x represent the number of h

ours parked. Write the function that models the cost C(x) of parking x hours where x is an integaer greater than 1

1 answer:

avanturin [10]2 years ago

5 0

C(x) = 5x + 2

This is because at 1 hour it only cost 7 dollars, so it should only have 2 added to the end.

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Which ratio is the simplest form of ? A 2:1 B 21:14 C 3:2 D 2:3

Oxana [17]

Answer:

D 2:3

Step-by-step explanation:

The ratio can't get any smaller.

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2 years ago

How much will be paid in taxes for a $49.50 pair of shoes with a 6% tax rate.

nalin [4]

Answer:

$2.97 is the tax. $52.47 is the Total.

Step-by-step explanation:

49.5x6%=2.97

2.97+52.47

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2 years ago

Find the vertex of the function given below y=x^2-2x+1

Ymorist [56]

Hey there! :)

Answer:

(1, 0).

Step-by-step explanation:

Convert from standard form to vertex form by completing the square:

y = x² - 2x + 1

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-1 = x² - 2x

Complete the square. Remember to add to both sides:

-1 + (1) = x² -2x + 1

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0 = (x - 1)²

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3 0

2 years ago

Help me I don’t really know what to say but I have to have 20 characters but please help

SashulF [63]

Answer:

14n

Step-by-step explanation:

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3 years ago

Approximate the area under the curve over the specified interval by using the indicated number of subintervals (or rectangles) a

devlian [24]

Answer:

The area under the function $\int\limits^3_1 {9-x^2} \, dx \approx 7.25.$ .

Step-by-step explanation:

We want to find the Riemann Sum for $\int\limits^3_1 {9-x^2} \, dx$ with 4 sub-intervals, using right endpoints.

A Riemann Sum is a method for approximating the total area underneath a curve on a graph, otherwise known as an integral.

The Right Riemann Sum is given by:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)$

where $\Delta{x}=\frac{b-a}{n}$

From the information given we know that a = 1, b = 3, n = 4.

Therefore, $\Delta{x}=\frac{3-1}{4}=\frac{1}{2}$

We need to divide the interval [1, 3] into 4 sub-intervals of length $\Delta{x}=\frac{1}{2}$ :

$\left[1, \frac{3}{2}\right], \left[\frac{3}{2}, 2\right], \left[2, \frac{5}{2}\right], \left[\frac{5}{2}, 3\right]$

Now, we just evaluate the function at the right endpoints:

$f\left(x_{1}\right)=f\left(\frac{3}{2}\right)=\frac{27}{4}=6.75$

$f\left(x_{2}\right)=f\left(2\right)=5=5$

$f\left(x_{3}\right)=f\left(\frac{5}{2}\right)=\frac{11}{4}=2.75$

$f\left(x_{4}\right)=f(b)=f\left(3\right)=0=0$

Next, we use the Right Riemann Sum formula

$\int\limits^3_1 {9-x^2} \, dx \approx \frac{1}{2}(6.75+5+2.75+0)=7.25$

7 0

3 years ago