<u>ANSWER:
</u>
Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%
<u>SOLUTION:
</u>
Given,
P = RS 2000
C.I = RS 2315.35
T = 3 years
We need to find the rate per annum. i.e. R = ?
We know that,
When interest is compound Annually:

Where p = principal amount
r = rate of interest
n = number of years



![$1+\frac{R}{100}=\sqrt[3]{1.157}$](https://tex.z-dn.net/?f=%241%2B%5Cfrac%7BR%7D%7B100%7D%3D%5Csqrt%5B3%5D%7B1.157%7D%24)



R = 5%
Hence, rate per annum is 5 percent.
Step-by-step explanation:
- A. linear equation
- D. None of the above
- B. Boundary line Broken line
- A solid line
- 6.sorry
Answer:
please stop all this love comments
Step-by-step explanation:
okk? that will be better
Answer: -4
Work: So, to get -4, we need to simplify the equation. If you see any equation with +(- that's subtraction. So, with the rule, this equation is basically 8-12, and that's -4.