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-BARSIC- [3]
3 years ago
5

Place thermometers near the edge of the table for easy retrieval.

Physics
1 answer:
Maurinko [17]3 years ago
7 0
This is a true and false question correct or did you accidentally put two truths ??
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Https://brainly.com/question/14419503?referrer=searchResults
Ludmilka [50]

Answer:

what

Explanation:

Is every thing okay

5 0
3 years ago
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Can we call centre of gravity centre of weight? ​
algol [13]

Answer:

Centre of gravity is a theoretical point in the body where the total weight of the body is thought to be concentrated. In a uniform gravitational field, the centre of gravity is identical to the centre of mass. Yet, the two points do not always coincide.

3 0
3 years ago
The formula d = 1.1 t 2 + t + 1 expresses a car's distance (in feet to the north of an intersection, d , in terms of the number
Phantasy [73]

d(t) = 1.1t² + t + 1

The constant speed required to cover the same distance between t = 3 to t = 5 is the same as the average speed over that same time interval. It is given by:

v = Δx/Δt

v = average speed, Δx = change in distance, Δt = elapsed time

Given values:

Δx = d(5) - d(3) = 19.6ft

Δt = 5s - 3s = 2s

Plug in and solve for v:

v = 19.6/2

v = 9.8ft/s

5 0
4 years ago
Read 2 more answers
The total mass of the train and its passengers is 750000kg. The train is traveling at a speed of 84m/s. The driver applies the b
fiasKO [112]

Answer:

|F| = 393750  N

Explanation:

Given that,

Total mass of the train, m = 750000 kg

Initial speed, u = 84 m/s

Final speed, v = 42 m/s

Time, t = 80 s

We need to find the net force acting on the train. The formula for force is given by :

F = ma

F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{750000\times (42-84)}{80}\\\\F=-393750\ N

So, the magnitude of net force is 393750  N.

4 0
3 years ago
A pilot heads his jet due east. The jet has a speed of 475 mi/h relative to the air. The wind is blowing due north with a speed
oksian1 [2.3K]

Explanation:

a. The velocity of the wind as a vector in component form will be represented as v vector:

    v=30j

b.The velocity of the jet relative to the air as a vector in component form will be represented as u vector

    u=475i

c. The true velocity of the jet as a vector will be represented as w:

  w=u+v

  w=475i+30j

d.  The true speed of the jet will be calculated as:

    IwI=\sqrt{(475)^2+(30)^2}

    IwI=\sqrt{225625+900}

    IwI=\sqrt{226525}

    IwI=476 mi/h

e. The direction of the jet will be:

tita=tan^{-1}\frac{30}{475}

tita=tan^{-1}(0.0632)

tita=3.62degrees,or,N86.38degreesS

7 0
3 years ago
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