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ExtremeBDS [4]
3 years ago
11

Simplify. StartStart Fraction StartFraction 16 Over a squared EndFraction plus StartFraction 24 Over ab EndFraction plus StartFr

action 9 Over b squared EndFraction OverOver StartFraction 16 Over a squared EndFraction minus StartFraction 9 Over b squared EndFraction End EndFraction Start StartFraction StartFraction 16 Over a squared EndFraction plus StartFraction 24 Over ab EndFraction plus StartFraction 9 Over b squared EndFraction OverOver StartFraction 16 Over a squared EndFraction minus StartFraction 9 Over b squared EndFraction End EndFraction equals nothing ​(Simplify your​ answer.)
Engineering
2 answers:
sertanlavr [38]3 years ago
5 0

Answer:

(3a + 4b)² / a²b²

Explanation:

This question is difficult to interpret, however the concept being tested in this question is the ability to simplify fractions with variables.

It is a basic rule that only like terms (as denominators) can be added and subtracted from each other, however if you need to add or subtract two fractions with different denominators, it is important to make sure you create a common denominator.

For example, in the beginning, the first fractions are:

16/a² + 24/ab + 9/b²

So it is important to make sure there is a common denominator between all 3 fractions. An easy way of doing this would be to multiply denominators together:

(16b²)/a²b² + (9a²)/a²b² + 24/ab

(9a²+16b²)/a²b² + 24/ab

So now it has gone from 3 fractions to 2, and then to 1:

(9a²+16b²)/a²b² + 24ab/a²b²

(9a² + 24ab + 16b²) / a²b²

Then all that needs to be done is simplify the numerator:

(3a + 4b)² / a²b²

inysia [295]3 years ago
5 0

Answer:

(3a + 4b)² / a²b²

Explanation:

This question is difficult to interpret, however the concept being tested in this question is the ability to simplify fractions with variables.

It is a basic rule that only like terms (as denominators) can be added and subtracted from each other, however if you need to add or subtract two fractions with different denominators, it is important to make sure you create a common denominator.

For example, in the beginning, the first fractions are:

16/a² + 24/ab + 9/b²

So it is important to make sure there is a common denominator between all 3 fractions. An easy way of doing this would be to multiply denominators together:

(16b²)/a²b² + (9a²)/a²b² + 24/ab

(9a²+16b²)/a²b² + 24/ab

So now it has gone from 3 fractions to 2, and then to 1:

(9a²+16b²)/a²b² + 24ab/a²b²

(9a² + 24ab + 16b²) / a²b²

Then all that needs to be done is simplify the numerator:

(3a + 4b)² / a²b²

Explanation:

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What is the simplified meaning of the word "engineering"​
juin [17]

Answer:

.

Explanation:

.

4 0
3 years ago
Help please its due today will mark you brainliest
Tems11 [23]

Answer:

launch- The first stage is ignited at launch and burns through the powered ascent until its propellants are exhausted. The first stage engine is then extinguished, the second stage separates from the first stage, and the second stage engine is ignited. The payload is carried atop the second stage into orbit

powered ascent-The first stage is ignited at launch and burns through the powered ascent until its propellants are exhausted. The first stage engine is then extinguished, the second stage separates from the first stage, and the second stage engine is ignited. The payload is carried atop the second stage into orbit

coasting flight-

When the rocket runs out of fuel, it enters a coasting flight. The vehicle slows down under the action of the weight and drag since there is no longer any thrust present. The rocket eventually reaches some maximum altitude which you can measure using some simple length and angle measurements and trigonometry.

ejection charge-At the end of the delay charge, an ejection charge is ignited which pressurizes the body tube, blows the nose cap off, and deploys the parachute. The rocket then begins a slow descent under parachute to a recovery. The forces at work here are the weight of the vehicle and the drag of the parachute.

slow decent- slow downs (i guess)

recovery-A recovery period is typically characterized by abnormally high levels of growth in real gross domestic product, employment, corporate profits, and other indicators. This is a turning point from contraction to expansion and often results in an increase in consumer confidence

Explanation:

6 0
4 years ago
A large increase in elevation can cause a carbureted engine to run ________ if not properly adjusted for the altitude. a Rich b
mash [69]

Answer:

B - Poor

Explanation:

As you get higher up, There is less oxygen which causes the engine to create less power.

3 0
3 years ago
A square-thread power screw is used to raise or lower the basketball board in a gym, the weight of which is W = 100kg. See the f
KIM [24]

Answer:

power = 49.95 W

and it is self locking screw

Explanation:

given data

weight W = 100 kg = 1000 N

diameter d = 20mm

pitch p = 2mm

friction coefficient of steel f = 0.1

Gravity constant is g = 10 N/kg

solution

we know T is

T = w tan(α + φ ) \frac{dm}{2}     ...................1

here dm is = do - 0.5 P

dm = 20 - 1

dm = 19 mm

and

tan(α) = \frac{L}{\pi dm}      ...............2

here lead L = n × p

so tan(α) = \frac{2\times 2}{\pi 19}

α = 3.83°  

and

f = 0.1

so tanφ = 0.1

so that φ = 5.71°

and  now we will put all value in equation 1 we get

T = 1000 × tan(3.83 + 5.71 ) \frac{19\times 10^{-3}}{2}  

T = 1.59 Nm

so

power = \frac{2\pi N \ T }{60}     .................3

put here value

power = \frac{2\pi \times 300\times 1.59}{60}

power = 49.95 W

and

as φ > α

so it is self locking screw

 

8 0
3 years ago
A house is losing heat at a rate of 1700 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Exp
Furkat [3]

Answer:

1700kJ/h.K

944.4kJ/h.R

944.4kJ/h.°F

Explanation:

Conversions for different temperature units are below:

1K = 1°C + 273K

1R = T(K) * 1.8

= (1°C + 273) * 1.8

1°F = (1°C * 1.8) + 32

Q/delta T = 1700kJ/h.°C

T (K) = 1700kJ/h.°C

= 1700kJ/K

T (R) = 1700kJ/h.°C

= 1700kJ/h.°C * 1°C/1.8R

= 944.4kJ/h.R

T (°F) = 1700kJ/h.°C

= 1700kJ/h.°C * 1°C/1.8°F

= 944.4kJ/h.°F

Note that arithmetic operations like subtraction and addition of values do not change or affect the value of a change in temperature (delta T) hence, the arithmetic operations are not reflected in the conversion. Illustration: 5°C - 3°C

= 2°C

(273+5) - (273+3)

= 2 K

5 0
4 years ago
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