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3 years ago

What impact does modulus elasticity have on the structural behavior of a mechanical design?

Engineering

1 answer:

devlian [24]3 years ago

8 0

Answer with Explanation:

The modulus of elasticity has an profound effect on the mechanical design of any machine part as explained below:

1) Effect on the stiffness of the member: The ability of any member of a machine to resist any force depends on the stiffness of the member. For a member with large modulus of elasticity the stiffness is more and hence in cases when the member has to resist a direct load the member with more modulus of elasticity resists the force better.

2)Effect on the deflection of the member: The deflection caused by a force in a member is inversely proportional to the modulus of elasticity of the member thus in machine parts in which we need to resist the deflections caused by the load we can use materials with greater modulus of elasticity.

3) Effect to resistance of shear and torque: Modulus of rigidity of a material is found to be larger if the modulus of elasticity of the material is more hence for a material with larger modulus of elasticity the resistance it offer's to shear forces and the torques is more.

While designing a machine element since the above factors are important to consider thus we conclude that modulus of elasticity has a profound impact on machine design.

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Consider the following ways of handling deadlock: (1) banker’s algorithm, (2) detect

Andrew [12]

Answer:

Explanation:

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3 years ago

Find the compressibility factor Z for oxygen at 3 MPa and 160 K.

saveliy_v [14]

Answer:

Z= 0.868

Explanation:

Given that

P= 3 MPa

T = 160 K

We know that

P v= Z R T

P= Pressure

v = specific volume

R= gas constant

T = Absolute temperature

Z= Compressibility factor

Here specific volume of gas is not given so we assume that specific volume gas

$v=0.012\ m^3/kg$

We know that for oxygen gas constant

R = 0.259 KJ/kg.K

Now by putting the values

P v = Z R T

3000 x 0.012 = Z x 0.259 x 160

Z= 0.868

So Compressibility factor is 0.868.

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3 years ago

A CPMT should include _____ who can oversee the security planning of the project and provide information on threats, vulnerabili

Talja [164]

Answer: information security managers

Explanation:

Information security managers is an individual in charge of making sure that company's or organization's equipments such as computers, network, data etc are protected against security breach, computer viruses, hackers, etc. The person also keep assets in confidentiality, integrity, and makes them available when needed. Failure to do this might lead to the loss of confidential data, security breach, cyber crimes, etc which will cause a serious set back in a company's operations especially in the information and technology department, it might also lead to fine sanctions from regulatory body for the failure to protect data, it will also lead to financial loss,etc.

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3 years ago

The transfer function of a typical tape-drive system is given by

maw [93]

Answer:

the range of K can be said to be : -3.59 < K< 0.35

Explanation:

The transfer function of a typical tape-drive system is given by;

$KG(s) = \dfrac{K(s+4)}{s[s+0.5)(s+1)(s^2+0.4s+4)]}$

calculating the characteristics equation; we have:

1 + KG(s) = 0

$1+ \dfrac{K(s+4)}{s[s+0.5)(s+1)(s^2+0.4s+4)]} = 0$

${s[s+0.5)(s+1)(s^2+0.4s+4)]} +{K(s+4)}= 0$

$s^5 + 1.9 s^4+ 5.1s^3+6.2s^2+ 2s+K(s+4) = 0$

$s^5 + 1.9 s^4+ 5.1s^3+6.2s^2+ (2+K)s+ 4K = 0$

We can compute a Simulation Table for the Routh–Hurwitz stability criterion Table as follows:

$S^5$ 1 5.1 2+ K

$S^4$ 1.9 6.2 4K

$S^3$ 1.83 $\dfrac{1.9 (2+K)-4K}{1.9}$ 0

$S^2$ $\dfrac{11.34-1.9(X)}{1.83}$ 4K 0

S $\dfrac{XY-7.32 \ K}{Y}$ 0 0

$\dfrac{1.9 (2+K)-4K}{1.9} = X$

$\dfrac{11.34-1.9(X)}{1.83}= Y$

We need to understand that in a given stable system; all the elements in the first column is usually greater than zero

So;

11.34 - 1.9(X) > 0

$11.34 - 1.9(\dfrac{3.8+1.9K-4K}{1.9}) > 0$

$11.34 - (3.8 - 2.1K)>0$

7.54 +2.1 K > 0

2.1 K > - 7.54

K > - 7.54/2.1

K > - 3.59

Also

4K >0

K > 0/4

K > 0

Similarly;

XY - 7.32 K > 0

$(\dfrac{3.8+1.9K-4K}{1.9})[11.34 - 1.9(\dfrac{3.8+1.9K-4K}{1.83}) > 7.32 \ K]$

0.54(2.1K+7.54)>7.32 K

11.45 K < 4.07

K < 4.07/11.45

K < 0.35

Thus the range of K can be said to be : -3.59 < K< 0.35

4 0

3 years ago

Based on bonding theory, explain why coefficient of expansion increases when you consider ceramics, metals and polymers

Mrrafil [7]

Answer:

The ratio that a material expands in accordance with changes in temperature is called the coefficient of thermal expansion. Because Fine Ceramics possess low coefficients of thermal expansion, their distortion values, with respect to changes in temperature, are low. The coefficients of thermal expansion depend on the bond strength between the atoms that make up the materials.

Explanation:

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4 years ago