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marishachu [46]
4 years ago
6

2 consecutive odd integers whose product is 63

Mathematics
1 answer:
il63 [147K]4 years ago
4 0

Answer:

The two numbers are 7 and 9; -7 and -9 is an alternative answer.

Step-by-step explanation:

Let the two consecutive odd integers be represented by x and (x+2).  Then x(x+2) = 63, or x^2 + 2x - 63 = 0, or (x-7)(x+9) = 0.  Then, x is either 7 or -9.  Check:  Does (7)(9) = 63?  YES

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A number increased by 4 is the same as 19 minus 2 times the number
ElenaW [278]

Hello from MrBillDoesMath!

Answer:

n = 5


Discussion:

Let the original number be "n"  Translating the problem  statement to mathematical symbolism:

n + 4 = 19 - 2n                   =>  add 2n to both sides

n + 2n + 4 = 19 - 2n + 2n  =>  combine like terms

3n + 4 = 19                        => subtract 4 from both sides

3n = 19 -4  = 15                 => divide both sides by 3

n = 15/3 =5


Check: Does 5 +4 = 19 - 2(5)? Does 9 = 9? Yes. so the value for n is confirmed correct.


Thank you,

MrB

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3 years ago
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