Question

Please solve and explain how. Photo attached

Answer 1

Answer:

Step-by-step explanation:

$\frac{2}{k^2-2k}=1-\frac{1}{k^2-2k}$

multiply by $\frac{k^2-2k}{1}$ on each side

$2=k^2-2k-1$

add 1 on both sides $3=k^2-2k$

make it equal 0

$0=k^2-2k-3$

Factor

$(k-3)(k+1)$

answer is 3 and -1