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n200080 [17]
2 years ago
14

Please solve and explain how. Photo attached

Mathematics
1 answer:
geniusboy [140]2 years ago
7 0

Answer:

Step-by-step explanation:

\frac{2}{k^2-2k}=1-\frac{1}{k^2-2k}

multiply by \frac{k^2-2k}{1} on each side

2=k^2-2k-1

add 1 on both sides 3=k^2-2k

make it equal 0

0=k^2-2k-3

Factor

(k-3)(k+1)

answer is 3 and -1

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