You have to convert the percent into a decimal before you convert it into a fraction then you simplify the fraction.
Hope this helps! :)
Step-by-step explanation:
f(3)=?
f(x)=2x+5
put x=3,
f(3)=2(3)+5=6+5=11
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g(2)=?
g(x)=x^2-3
put x=2,
g(2)=2^2-3=4-3=1
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g(f(-1))=?
g(x)=x^2-3
and f(-1)=2(-1)+5= -2+5=3
so g(f(-1))=3^2-3=9-3=6
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f(g(-1))=?
f(x)=2x+5
g(x)=g(-1)=(-1)^2-3=1-3= -2
f(g(-1))=2(-2)+5= -4+5=1
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g(f(x))=?
g(x)= x^2-3
put x=f(x),
g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25
In the case of a circle, the formula for area, A, is A = pi * r^2, where r is the circle's radius. Since we know that a semicircle is half of a circle, we can simply divide that equation by two to calculate the area of a semicircle. So, the formula for the area of a semicircle is A = pi * r^2/2
Answer:
1. S(1) = 1; S(n) = S(n-1) +n^2
2. see attached
3. neither
Step-by-step explanation:
1. The first step shows 1 square, so the first part of the recursive definition is ...
S(1) = 1
Each successive step has n^2 squares added to the number in the previous step. So, that part of the recursive definition is ...
S(n) = S(n-1) +n^2
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2. See the attachment for a graph.
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3. The recursive relation for an arithmetic function is of the form ...
S(n) = S(n-1) +k . . . . . for k = some constant
The recursive relation for a geometric function is of the form ...
S(n) = k·S(n-1) . . . . . . for k = some constant
The above recursive relation is not in either of these forms, so it is neither geometric nor arithmetic.