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3 years ago

If h(x) = x - 7 and g(x) = x^2 , which expression is equivalent to (gOh)(5)?

Mathematics

1 answer:

Ann [662]3 years ago

7 0

(5 - 7)^2 is your answer

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Which phrase describes an unknown or changeable quantity?

Flura [38]

Answer:

That is a variable.

Step-by-step explanation:

- opposed to a constant which is known and does not change.

3 0

2 years ago

Let f(x)=x^2+5x-8. What is the average rate of change from x = 2 to x = 6? Enter the answer in the box ___

koban [17]

Answer:

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [2, 6 ]

f(b) = f(6) = 6² + 5(6) - 8 = 36 + 30 - 8 = 58

f(a) = f(2) = 2² + 5(2) - 8 = 4 + 10 - 8 = 6

Hence

average rate of change = $\frac{58-6}{6-2}$ = $\frac{52}{4}$ = 13

5 0

3 years ago

A card is drawn from a standard deck of 5252 playing cards. What is the probability that the card will be a heart or a face card

mr_godi [17]

Answer:

The probability that the card will be a heart or a face card is P=0.4231.

Step-by-step explanation:

We have a standard deck of 52 cards.

In this deck, we have 13 cards that are a heart.

We also have a total of 12 face cards (4 per each suit). So there are 3 face cards that are also a heart.

To calculate the probability that a card be a heart or a face card, we sum the probability of a card being a heart and the probability of it being a face card, and substract the probability of being a heart AND a face card.

We can express that as:

$P(H\,or\,F)=P(H)+P(F)-P(H\&F)\\\\P(H\,or\,F)=13/52+12/52-3/52=22/52=0.4231$

4 0

3 years ago

Raise c to the 3rd power, then triple the result

777dan777 [17]

Step-by-step explanation:

Raise c to the 3rd power:

${c}^{3}$

Triple the amount (Multiply by 3):

$3( {c}^{3} )$

5 0

2 years ago

A sporting goods store sells basketballs for $22. They paid $8 for each

saveliy_v [14]

Answer:

275% of increase

Step-by-step explanation:

Make a porportion and cross multiply and you'll get your answer and also stop using this app to cheat please its not going to help ou in the long run, and its not fair to the teachers who teach you this material just for you to cheat.

6 0

2 years ago