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Mrac [35]
3 years ago
9

Joe and Ben are saving money for a new x-box game. Joe has saved $15.00 in 2 weeks and $37.50 in 5 weeks. Ben's savings are repr

esented by the equation
y=8.25x
y=8.25x
.
Find the difference in their savings each week?
Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0

Answer:

37.50/5 = $7.50/week

so the difference is 8.25-7.50 = $0.75/week

Step-by-step explanation:

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Answer:

Part A) The length of rectangle is 3x\ cm

Part B) The perimeter of the square is 3x\ cm

Part C) 20\ cm

Part D) 39\ cm^{2}

Step-by-step explanation:

Part A) Find the length of the rectangle

we know that

The perimeter of rectangle is equal to

P=2(L+W)

we have

P=8x\ cm

W=x\ cm

substitute and solve for L

8x=2(L+x)

4x=(L+x)

L=4x-x=3x\ cm

Part B) Find the perimeter of the square

we know that

The perimeter of a square is

P=4b

we have that

b=(1/4)L

substitute the value of L

b=(1/4)3x=(3/4)x\ cm

Find the perimeter of the square

P=4(3/4)x=3x\ cm

Part C) Find how many cm greater the rectangle's perimeter than the square's perimeter if x=4

<u>Find the value of rectangle's perimeter</u>

P=8x\ cm ------> P=8(4)=32\ cm

<u>Find the value of square's perimeter</u>

P=3x\ cm ------> P=3(4)=12\ cm

<u>Find the difference</u>

32\ cm-12\ cm=20\ cm

Part D) Find how many square cm greater the rectangle's area is than the square's area if x=4

<u>Find the value of rectangle's area</u>

A=(3x)(x)=3x^{2}\ cm^{2} ------> A=3(4^{2})=48\ cm^{2}

<u>Find the value of square's area</u>

A=((3/4)x)^{2}\ cm^{2} ------> A=((3/4)(4))^{2}=9\ cm^{2}

<u>Find the difference</u>

48\ cm^{2}-9\ cm^{2}=39\ cm^{2}

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3 years ago
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