Answer:
Step-by-step explanation:
the answer is basically 4.5% and the 6%
Y=2x+5 so order pair would be (1,7) and (2,9)
Let us denote the semi arcs as congruent angles. This means that angles FEJ and EFJ are congruent (That is, they have the same measure). Since angles FEJ and EFJ have the same measure, this implies that sides EJ and FJ are equal. Since angles EJK and FJH are supplementary angles to angle EJF, this implies that EJK and FJH have the same measure.
Using the Angle Side Angle (SAS) criteria, we determine that triangles EKJ and triangle FJH are congruent. This implies that sides EK and FH are equal and that angles EKJ and FHJ are congruent. Note that angle EKJ is the same as EKF and that FHJ is the same as FHE.
Once again, since angles EKF and FHJ are congruent, and angle EKD is supplementary to the angle EKJ when angle FHG is supplementary to angle FHJ, then we have that angles EKD and angle FHG are congruent.
Using again the SAS criteria, we determine that triangles EKD and FHG are congruent.
From this reasoning, we have proved the following facts:
Triangle DEK is congruent to triangl GFH
Angle EKF is congruent to angle FHE
Segment EK is the same as segment FH
Answer:
y = -20x + 100
Step-by-step explanation:
As per your requirement For Part B, the solution is
The equation in slope-intercept form to model the relations is below:-
To reach 2 points on the graph the line passes through
lets use p1(0, 100), p2(1, 80)
now we will compute the slope:
= -20
and now use line equation in form point-slope:
y - y1 = m(x - x1)
y - 100 = -20(x - 0)
y = -20x + 100
The image is decomposed as follows: H1 and H2. Where original graph is Hx.
<h3>Are the images (attached) valid decompositions of the original graph?</h3>
- Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
- H1 ∪ H2 = Hx
- They have no edges in common.
Hence, {H1 , H2} are valid decomposition of G.
<h3>What is a Graph Decomposition?</h3>
A decomposition of a graph Hx is a set of edge-disjoints sub graphs of H, H1, H2, ......Hn, such that UHi = Hx
See the attached for the Image Hx - Pre decomposed and the image after the graph decomposition.
Learn more about decomposition:
brainly.com/question/27883280
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