Question

Fred has $200. He wants to purchase a gym bag for $26 and as many pair of shoes as he can. Each pair of shoes is $45. What is the maximum number of pairs of shoes he can
purchase in addition to the gym bag?

Answer 1

Answer:

3 shoes

Step-by-step explanation:

You can set up an equation to solve this question like this:

200=45s+26

174=45s

174/45=s

s=3.867

You can't have a part of a shoe, so you have to round down to get 3 shoes

Answer 2

Answer:

3

Step-by-step explanation:

In order to get the answer to this question you subtract in till you can no longer subtract after subtracting the cost of the bag.

What we do know:

$M=200$

$B=26$

$S=45$

$200-26=174$

$174-45=129$

$129-45=84$

$84-45=39$

$S=3$

Hope this helps