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Arlecino [84]
3 years ago
9

Help plsssssssssssssssssssssssssssssss

Mathematics
1 answer:
Zina [86]3 years ago
4 0

9514 1404 393

Answer:

  (16, -23)

Step-by-step explanation:

We assume your notation means the figure is dilated by a factor of 3 with the origin as the center of dilation, then it is translated 2 units left and 4 units up.

These transformations can be written as ...

  (x, y) ⇒ (3x, 3y) . . . . . . . dilation by a factor of 3 about the origin

  (x, y) ⇒ (x -2, y +4) . . . . translation by (-2, 4)

These two transformations together give you ...

  (x, y) ⇒ (3x -2, 3y +4)

  (6, -9) ⇒ (3·6 -2, 3(-9) +4) = (18 -2, -27 +4) = (16, -23)

The point is transformed to (16, -23).

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Evaluate the limit as h goes to 0 of (3+h)^4 -81/h
Montano1993 [528]

Answer:6

Step-by-step explanation:Take the derivative of the numerator and denominator, then evaluate the limit.

8 0
3 years ago
In a quiz contest, 4 marks were awarded for a correct answer and -2 marks were given for an incorrect answer. If James gave 5 in
Zina [86]

9514 1404 393

Answer:

  10

Step-by-step explanation:

For c correct answers and 5 incorrect answers, James's score is ...

  4c -2(5) = 30

  4c = 40 . . . . . . add 10

  c = 10 . . . . . . . . divide by 4

James gave 10 correct answers.

4 0
3 years ago
Read 2 more answers
How to solve proportion using cross products,k8=14/4
luda_lava [24]
Multiply the variable k times 4 would give you 4k.
Then cross multiply 14x8 = 112

Therefore, you would have 4k = 112.
Divide 112 by 4 to get your answer!
6 0
3 years ago
In triangle ABC, c is the hypotenuse, 0=25°, and b =3, Find the length of c ?
Charra [1.4K]

Answer:

\large\boxed{c\approx3.31}

Step-by-step explanation:

Use cosine:

cosine=\dfrac{adjacent}{hypotenuse}

\cos\theta=\dfrac{b}{c}

We have:

\theta=25^o\to\cos25^o\approx0.9063\\\\b=3

Substitute:

\dfrac{3}{c}=0.9063

\dfrac{3}{c}=\dfrac{9063}{10000}          <em>cross multiply</em>

9063c=30000          <em>divide both sides by 9063</em>

c\approx3.31

8 0
3 years ago
A rectangular vegetable patch has an area of 56 square meters and a
vredina [299]

Answer:

The dimensions of the vegetable patch is 8 m by 7 m.

Step-by-step explanation:

Area of a vegetable patch is 56 square meters and the perimeter is 30 m.

If l is length and b is breadth, then area and perimeter of a rectangle is given by :

A=l\times b

P=2(l+b)

Substituting the values in the above formulas as :

l\times b=56\ ....(1)

and

2(l+b)=30\\\\l+b=15\ .....(2)

We need to solve equation (1) and (2) to find the values of l and b such that :

Equation (2), l = 15 - b

Equation (1) becomes,

(15-b)b=56\\\\b=7\ m, 8\ m

If b = 7 m, so, l = 8 m

If b = 8 m, l = 7 m

So, the dimensions of the vegetable patch is 8 m by 7 m.

4 0
3 years ago
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