4 divided by 1/7 = 28 i believe. sorry if i’m wrong
x - y = 14
given the ratio x : y = 5 : 3
then let x = 5x and y = 3x, hence equation can be expressed as
5x + 3x = 56
8x = 56 ( divide both sides by 8 )
x = 7
Hence x = 5 × 7 = 35 and y = 3 × 7 = 21
Thus x - y = 35 - 21 = 14
Add the 6x to both sides. Then divide both sides by 2 to get y by itself.
y <= 6x + 42
Note: if it were a -2y, you’d have to flip the inequality sign when dividing by that negative 2.
:)
Item 4 Find the median, first quartile, third quartile, and interquartile range of the data. 132,127,106,140,158,135,129,138 med
Ket [755]
Answer:
133.5, 127.5, 139.5, 12
Step-by-step explanation:
order data:
106, 127, 129, 132, 135, 138, 140, 158
Median:
The middle number: (8+1)/2 = 4.5 between the 4&5 numbers
= (135-132)/2= 1.5
1.5 + 132 = 133.5
lower quartile (1st quartile):
(8+1)/4 = 2.25 between the 2&3 numbers
(129+127)/4=0.5
0.5+127 = 127.5
upper quartile(3rd quartile):
(8+1)/4 x3 = 6.75 between the 6&7 numbers
(140-138)/4 x3 = 1.5
1.5 + 138 =139.5
Interquartile range:
139.5-127.5= 12
hope this helps
The answer is= there are 126 5p coins
the reason for this is that
-630 is simplified to 5,
-so 1/5 is really 126/630,
(630 divided by 5 is 126)
- and so 2/5 is 126 x 2 =252/630
- there are only 3 parts left, and if 1p has more parts than 5p,
-then 1p takes up 2/5 of the bag
-and 5p takes up 1/5 of the bag
