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svp [43]
3 years ago
9

Fmfrjrjdjejeidisiiiidiidsisiiisi​

Mathematics
1 answer:
SVEN [57.7K]3 years ago
4 0

Answer:

The answer is,

r =  \frac{3t}{t - 1}

Step-by-step explanation:

t =  \frac{r}{ r - 3}

Firstly, you have to get rid of fraction by multiplying (r-3) to both side and expand out:

t × (r-3) = r/(r-3) × (r-3)

rt - 3t = r

Then you have to move all the "r" variables to one side and other variables to the other side:

rt - r = 3t

You can make "r" as a subject by taking out the common term, you can see that the common term on the left is "r" so you can bring out:

r(t-1) = 3t

r = 3t/(t-1)

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If you have 720 pt/h how many qt/min is it
Maurinko [17]
So,

720 pt./hr.

2 pt. = 1 qt.

720/2 = 360

360 qt./hr.

Now, since there are 60 mins. in 1 hr., multiply the number by 60.

360(60) = 21600

720 pt./hr. = 21,600 qt./min.
6 0
3 years ago
The assessed value of a certain house is Rs.15 000. If the the relevant council institutions charges 5℅ of the value of the hous
bezimeni [28]

Answer:

15000×5/100=100/100x

150×5=x

750=x

Assessed value that you have to pay for a year is Rs.750.00

Step-by-step explanation:

Have a great day!

4 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv
ch4aika [34]

Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

f(x)=a(x-c)(x-d)

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

-4=a(1-3)(1+1)

-4=a(-2)(2)

a=1

therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

8=a(-1-1)(-1+3)

8=a(-2)(2)

a=-2

therefore

The function is equal to

f(x)=-2(x-1)(x+3)

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

-8=a(2-6)(2+2)

-8=a(-4)(4)

a=0.5

therefore

The function is equal to

f(x)=0.5(x-6)(x+2)

3 0
3 years ago
The two polygons above are similar. The scale factor of the smaller polygon to the larger polygon is 3. The area of the smaller
Softa [21]
You would think it was 3 * 12 = 36. Not so. All polygons have to be broken down into some figure that will give 2 dimensions that are at right angles to each other. That would mean that
d1 * d2 = Area for the small polygon
3d1 * 3d2 = area of the larger polygon

What that means is that the area of the larger one is 9 times the smaller one.
Area large = 12 * 9 = 108 square units. <<<<< answer.

If you find this hard to be leave try it with a square.
Suppose you have a square (the small one) that is 3 cm by 3 cm
The small one has an area of 3*3 cm^2 = 9 cm

Now you have another square that is 3 times larger. That means that each side is 3*3 = 9
So s = 9
Area = s^2
Area = 9^2 = 81 cm^2
81 is 9 times larger than 9 just as you would think. 


4 0
3 years ago
Identify the transformation(s) where the image has the opposite orientation as the preimage.
Dmitry_Shevchenko [17]
<span>glide reflection and reflection</span>
6 0
3 years ago
Read 2 more answers
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