Answer:
If sound waves of the same energy were passed through a block of wood and a block of steel, which is more dense than the wood, the molecules of the steel would vibrate at a slower rate. Sound moves faster through denser air because the molecules are closer together in dense air and sound can be more easily passed on.
Explanation:
The first one is: head
Second one is: 10 trillion km
Answer:
a. a = 
b. T = -0.81 N
Explanation:
Given,
- weight of the lighter block =
- weight of the heavier block =
- inclination angle =
- coefficient of kinetic friction between the lighter block and the surface =
- coefficient of kinetic friction between the heavier block and the surface =
- friction force on the lighter block =
- friction force on the heavier block =
Let 'a' be the acceleration of the blocks and 'T' be the tension in the string.
From the f.b.d. of the lighter block,
From the f.b.d. of the heavier block,
From eqn (1) and (2), we get,
![\Rightarrow a\ =\ \dfrac{g(w_1sin\theta\ -\ \mu_1w_1cos\theta\ +\ w_2sin\theta\ +\ \mu_2w_2cos\theta)}{w_1\ +\ w_2}\\\Rightarrow a\ =\ \dfrac{g[sin\theta(w_1\ +\ w_2)\ +\ cos\theta(\mu_2w_2\ -\ \mu_1w_1)]}{w_1\ +\ w_2}\\](https://tex.z-dn.net/?f=%5CRightarrow%20a%5C%20%3D%5C%20%5Cdfrac%7Bg%28w_1sin%5Ctheta%5C%20-%5C%20%5Cmu_1w_1cos%5Ctheta%5C%20%2B%5C%20w_2sin%5Ctheta%5C%20%2B%5C%20%5Cmu_2w_2cos%5Ctheta%29%7D%7Bw_1%5C%20%2B%5C%20w_2%7D%5C%5C%5CRightarrow%20a%5C%20%3D%5C%20%5Cdfrac%7Bg%5Bsin%5Ctheta%28w_1%5C%20%2B%5C%20w_2%29%5C%20%2B%5C%20cos%5Ctheta%28%5Cmu_2w_2%5C%20-%5C%20%5Cmu_1w_1%29%5D%7D%7Bw_1%5C%20%2B%5C%20w_2%7D%5C%5C)
![\Rightarrow a\ =\ \dfrac{9.81\times [sin30^o\times (3.0\ +\ 7.0)\ +\ cos30^o\times (0.31\times 7.0\ -\ 0.13\times 3.0)]}{3.0\ +\ 7.0}\\\Rightarrow a\ =\ 6.4\ m/s.](https://tex.z-dn.net/?f=%5CRightarrow%20a%5C%20%3D%5C%20%5Cdfrac%7B9.81%5Ctimes%20%5Bsin30%5Eo%5Ctimes%20%283.0%5C%20%2B%5C%207.0%29%5C%20%2B%5C%20cos30%5Eo%5Ctimes%20%280.31%5Ctimes%207.0%5C%20-%5C%200.13%5Ctimes%203.0%29%5D%7D%7B3.0%5C%20%2B%5C%207.0%7D%5C%5C%5CRightarrow%20a%5C%20%3D%5C%206.4%5C%20m%2Fs.)
part (b)
From the eqn (2), we get,
Solid, Malleable, and it reflects light and heat. Those are (some) physical properties.
The correct answer No the velocity is not zero anywhere For an object being launched at ground level at a tilted non-zero initial velocity, and horizontal or vertical components of the velocity is zero at maximum height .
Because velocity is a vector (it has magnitude and direction), the overall velocity of an object can be calculated by adding the x and y components: v2 = vx2 + vy2. Meters are used to express horizontal and vertical distances (m). The horizontal velocity component (vx) describes the effect of velocity on horizontal displacement of the projectile.
The vertical velocity component (vy) describes the effect of velocity on vertical displacement of the projectile. The vertical component of a projectile's velocity is momentarily zero (vy = 0 m/s) when it reaches maximum height. The horizontal component of its velocity, however, is not zero.
Learn more about components of velocity here :-
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