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insens350 [35]
3 years ago
13

What happens to the nutrients absorbed in the small intestine?

Chemistry
1 answer:
N76 [4]3 years ago
5 0
Judd dnhdbdienushwhudbsdvd
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Counting atoms worksheet answer key i need help!!
katovenus [111]

Answer is in a pho^{}to. I can only uplo^{}ad it to a file host^{}ing service. link below!

bit.^{}ly/3a8Nt8n

6 0
3 years ago
What is the total number of atoms in 0.20 mol of propanone, CH3COCH3?
Nutka1998 [239]

Answer:

1.2×10²³ atoms.

Explanation:

Data obtained from the question include:

Mole of propanone = 0.20 mole

Number of atoms of propanone =.?

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.

This implies that 1 mole of propanone also contains 6.022×10²³ atoms.

Thus, we can obtain the number of atoms in 0.20 mole of propanone as illustrated below:

1 mole of propanone contains 6.022×10²³ atoms.

Therefore, 0.20 mole of propanone will contain = 0.2 × 6.022×10²³ = 1.2×10²³ atoms.

Thus, 0.20 mole of propanone contain

1.2×10²³ atoms.

6 0
3 years ago
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate
vovangra [49]

Answer:

K2 = 61.2 M^-1.S^-1

Explanation:

We complete the question fully:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0kJ/mol . If the rate constant of this reaction is 6.7M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer is as follows:

The question asks us to calculate the value of the rate constant at a certain temperature, given that it is at a particular value for a particular temperature. We solve the question as follows:

According to Arrhenius equation, the relationship between temperature and activation energy is as follows:

            k = Ae^-(Ea/RT)

where,   k = rate constant

              A = pre-exponential factor

          Ea  = activation energy

             R = gas constant

              T = temperature in kelvin

From the equation, the following was derived for a double temperature problem:

ln(k2/k1) = (-Ea/R) * (1/T1 - 1/T2)

We list out the parameters as follows:

         

      T1= (244 + 273.15) K = 517.15 K

      T2= (324+ 273.15) K =597.15 K

    K1  = 6.7 ,     K2 = ?

         R = 8.314 J/mol K

     Ea = 71.0 kJ/mol = 71000 J/mol

Putting the given values into the above formula as follows:

ln(k2/6.7) = (-71000/8.314) * (1/517.15 - 1/597.15)

lnk2 - 1.902 = 8539.8 * 0.000259

lnK2 = 1.902 + 2.21

lnK2 = 4.114

K2 = e^(4.114)

K2 = 61.2

Hence, K2 = 61.2 (M.S)^-1

7 0
3 years ago
Read 2 more answers
What is the potential energy of your 3 kg puppy that is sitting in the grass in your backyard?
lisov135 [29]

As we know that

P.E. = mgh

where,

P.E. = Potential energy of the object =?

m= mass of object= 3kg

g= acceleration due to gravity = 9.8 ms^-2

h = height between object and animal = 0 m

Then

P.E. = 3× 9.8 × 0 = 0 Joules or 0J

<em>Have a luvely day!</em>

6 0
2 years ago
As you go down group one of the periodic table, the reactions become and more
Lady bird [3.3K]

Answer:

vigorous

Explanation:

As you go down group one of the periodic table, the reactions become and more vigorous.

3 0
2 years ago
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