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dolphi86 [110]
3 years ago
5

What are the chemical formulas for..

Chemistry
1 answer:
andrezito [222]3 years ago
6 0
S4O5
S3O
SeF6
N4S5
CCl9

All numbers should be subscripts
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If the speed of a sound wave increases what other property of the wave must also increase when all other wave properties are hel
kati45 [8]
<h2>Frequency</h2>

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

Wave speed is the speed at which a wave travels.

Let the wave speed be v

Let the wave frequency be f

Let the wave length be l

The wave speed,frequency and wave length are related by the equation v=f\times l.

When v increases,f increases on the other side to maintain equality when no other property is changing.

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4 years ago
Which part of the fuel cell does A represent?
Bad White [126]

I think the anwer is electrolyte :)... i had it on a test a couple days ago.

8 0
3 years ago
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Why are physical properties such as hardness or cleavage useful to geologists when identify minerals?
nevsk [136]

Answer:

Physical properties are controlled by the mineral's chemical composition and atomic structure, this combination is distinct in each mineral.

Explanation:

Hello,

Since the physical properties depend on the mineral's chemical composition and the atomic structure (molecular arrangement), we can distinguish different minerals by measuring out hardness, cleavage and other properties in order to analyze their behavior under several conditions and subsequently  use them in a particular application.

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5 0
3 years ago
Arizona was the site of a 400,000-acre wildfire in June 2002. How much carbon dioxide (CO2) was produced into the atmosphere by
kodGreya [7K]

Answer:

2.97 × 10¹³ g

Explanation:

First, we have to calculate the biomass the is burned. We can establish the following relations:

  • 2.47 acre = 10,000 m²
  • 10 kg of C occupy an area of 1 m²
  • 50% of the biomass is burned

The biomass burned in the site of 400,000 acre is:

400,000acre\times\frac{10,000m^{2} }{2.47acre} \times \frac{10kgC}{m^{2} } \times 50\% = 8.10 \times 10^{9} kgC

Let's consider the combustion of carbon.

C(s) + O₂(g) ⇒ CO₂(g)

We can establish the following relations:

  • The molar mass of C is 12.01 g/mol
  • 1 mole of C produces 1 mole of CO₂
  • The molar mass of CO₂ is 44.01 g/mol

The mass of  produced is CO₂:

8.10 \times 10^{12}gC \times \frac{1molC}{12.01gC} \times \frac{1molCO_{2}}{1molC} \times \frac{44.01gCO_{2}}{1molCO_{2}} =2.97 \times 10^{13} gCO_{2}

4 0
3 years ago
What is the percent by mass of oxygen in ca(oh)2? [formula mass = 74.1]
andre [41]
16(2)/74.1=.431

.431x100= 43.1%
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3 years ago
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