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borishaifa [10]
3 years ago
5

Solve log2(t+1)-log2(t-1)

Mathematics
1 answer:
baherus [9]3 years ago
5 0
I think 4glo is the answer
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19. Please help!!! Reporting all fake answers!:-(
dimaraw [331]

my answer is (a) I think

7 0
3 years ago
Gus and Ike carried a total of 84 books to the library. If Gus carried 5 as many books as Ike, how many books did they each carr
Alexus [3.1K]

Answer:

They each carried 25 books each.

Step-by-step explanation:

You get this by doing

84/5=16.8

then you do

84/2/5= 8.4

8.4+16.8=25.2

but round to whatever 5 or higher bump up below 5 keep the same

so your answer results in 25.

3 0
4 years ago
The number of internet users in mexico between 2004 and 2008 can be modeled as u(t) = 8.02(1.17t) million users where t is the n
maxonik [38]

Answer:

a) 1.479 Million

b) 36.9%

c) 13.668%

Step-by-step explanation:

The complete question is attached in the image below.

The number of internet users in Mexico between 2004 and 2008 is modelled by the following equation:

u(t)=8.02(1.17)^{t}

Where, u(t) is in millions and t is the number of years since 2004.

Part a) Rate of change of internet users between 2004 and 2006

The rate of change of a function is defined as:

\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}

We have to find the rate of change between 2004 and 2006. For 2004 t = 0, and for 2006, t = 2. So the rate of change for the given function will be:

\frac{u(2)-u(0)}{2-0}\\\\ =\frac{8.02(1.17)^{2}-8.02(1.17)^{0}}{2}\\\\ =1.479

Thus, the average rate of change in number of internet users in Mexico from between 2004 and 2006 was 1.479 million.

Part b) Percentage change of internet users between 2004 and 2006

The formula to calculate the percentage change is:

\frac{\text{New value - Original Value}}{\text{Original Value}} \times 100\%

Here, New value means the users in 2006 and original value means the users in 2004.

Using the values in this formula, we get:

\frac{8.02(1.17)^{2}-8.02(1.17)^0}{8.02(1.17)^{0}} \times 100\%\\\\  =36.89\%

Thus, the percentage change in the number of internet users between 2004 and 2006 was 36.89%

Part c) Percentage of internet users in 2008

For 2008, t would be equal to 4.

So, the number of internet users in Mexico in 2008 would be = 8.02(1.17)^{4}=15.02857542 million = 15,028,575 (rounded to nearest integer)

Total population of Mexico in 2008 = 109,955,400

We have to calculate what percentage of Mexico population was Internet users in 2008. The formula for this would be:

\frac{\text{Concerned Value}}{\text{Total Value}} \times 100\%

Here, concerned value is the number of internet users and total value is the total population. Using the values in this formula we get:

\frac{15028575}{109955400} \times 100\%\\\\=13.668\%

Thus, 13.668% of the population was internet users in 2008 in Mexico.

5 0
3 years ago
If 3x-3+2x-8 what does x equal
My name is Ann [436]
3x + 2x = 5x
-3 - 8 = -11

5x - 11 = 0
5x - 11 (+11) = 0 (+11)
5x = 11
5x/5 = 11/5

x = 11/5

hope this helps
6 0
3 years ago
Read 2 more answers
The polynomial 3x2 – 10x + 8 has a factor of 3x – 4. What is the other factor of 3x2 – 10x + 8?
anyanavicka [17]

Answer:

Second factor is (x - 2).

Step-by-step explanation:

The given polynomial is 3x² -10x + 8 has a factor (3x - 4) and we have to find the other factor.

Now we will factorize the given polynomial to get the other factor.

3x² - 10x + 8

[ Here 8×3 = 24( multiplication of constant term 8 and coefficient of highest degree term) and 6 + 4 = 10 ]

= 3x² - 6x - 4x + 8

= 3x(x - 2) - 4(x - 2)

= (3x -4)(x -2)

In this factorized form we get two factors as (3x -4) and (x -2).

Therefore the second factor is (x - 2).

6 0
3 years ago
Read 2 more answers
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