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borishaifa [10]
2 years ago
5

Solve log2(t+1)-log2(t-1)

Mathematics
1 answer:
baherus [9]2 years ago
5 0
I think 4glo is the answer
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Help me please. Can somebody please help me.
Monica [59]

Answer:

oh my :o

Ok so just mutiply

Step-by-step explanation:

4 0
3 years ago
Which symbol correctly compares these fractions? −4/5 −8/9
mrs_skeptik [129]

Answer:

" > "

Step-by-step explanation:

-4/5=4x9 5×9

-4/5 = - 36/ 45

-8/9=8×5 9×5

-8/9 =-40/45

-36/ 45 > -40/45

-4/5 > -8/9

in this case - 4/5 is closer to 0

4 0
1 year ago
Read 2 more answers
The difference between the square of two numbers is five. Twice the square of the second number is subtracted from three times t
svet-max [94.6K]
Let us assume the first number to be = x
Let us assume the second number to be = y
Then
x^2 - y^2 = 5
x^2 = y^2 + 5
And
3x^2 - 2y^2 = 19
Multiplying the first equation by -2, we get
- 2x^2 + 2y^2 = - 10
Now subtracting the two equations, we get
x^2 = 9
x = 3
Putting the value of "x" in the first equation, we get
(3)^2 - y^2 = 5
9 - y^2 = 5
y^2 = 4
y = 2

I hope that the procedure is clear enough for you to understand and this is the answer that you were looking for.
5 0
3 years ago
Few math questions TIME IS RUNNING OUT!! PLEASE HELP!!!!
olya-2409 [2.1K]
1.

|5+6x|\ \textless \ 13\\\\-13\ \textless \ 5+6x\ \textless \ 13

so

\begin{cases}5+6x\ \textless \ 13\\5+6x\ \textgreater \ -13\end{cases}

Answers B and D.

2.

|x+9|\geq11\\\\x+9\ \textgreater \ 11\qquad\vee\qquad x+9\leq-11\\\\
\boxed{x\geq2\qquad\vee\qquad x\leq-20}

Answer D.

3.

The same as point 2. Answer D.

4.

Answer C.

3 0
3 years ago
Find the least common denominator of the two fractions from part B. To do this, list and compare the first five multiples of the
algol [13]

Answer:Find the least common denominator of the two fractions from part B. To do this, list and compare the first five multiples of the denominators. The smallest number that appears in both lists is the least common denominator. Show your work.

Step-by-step explanation:

4 0
3 years ago
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