Answer: The Radius is the distance from the center outwards. The Diameter goes straight across the circle, through the center. The Circumference is the distance once around the circle.
The formula for calculating the radius is different from calculating the diameter
Find radius
r= diameter/ 2
Radius is half of a diameter
While diameter is
d=2r
Step-by-step explanation:
Answer:
B 4,500
Step-by-step explanation:
I basically just guessed and if hes paying the interest then its gotta be a bit less then the price of the car I think if it's wrong my apologies
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
Answer:
120°
Step-by-step explanation:
All the angles of an equilateral triangle are equal, and hence have a measure of 60°.
∵ ∠AGF is a part of equilateral Δ AGF, m∠AGF = 60°.
∵ ∠FGE is a part of equilateral Δ AGF, m∠FGE = 60°.
Also note that ∠AGE = ∠AGF + ∠FGE.
⇒ m∠AGE = m∠AGF + m∠FGE
⇒ m∠AGE = 60° + 60°
= 120°.
