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anyanavicka [17]
3 years ago
10

For the expression 6 – y + 3, determine the coefficient for the variable term.

Mathematics
1 answer:
san4es73 [151]3 years ago
7 0

Answer:

-1

Step-by-step explanation:

Any variable without a visible coefficient means it has a coefficient of 1. Since it's negated, the coefficient is -1.

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Martin's test scores are 84, 72, 94, 83, and 61. What is the range of the test scores?
sammy [17]

Answer:

33.

Step-by-step explanation:

In order to find range, you must subtract the largest amount given by the smallest amount. In this case, it would be 94-61=33.

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I could only find a single semi-complete question on that paper due to the quality of the picture.  <u>The carbon dioxide and water escape from the tube, because as gases, they do not have a definite shape or volume, and instead expand to fit whatever container they are in.</u>

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I hated probability in middle school. I'm not 100% sure but I would go with the 3rd answer choice, 3/100.
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3 years ago
What is a times b times c =0 and a and b are integers greater than 10, what must c equal
GuDViN [60]

A x B x C = 0 Where A and B are integers > 10 Any value multiplied by 0 = 0 Therefore C = 0

5 0
3 years ago
PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.
anygoal [31]

Option C: x=0 and x=\frac{5}{2} are the solutions.

Explanation:

The equation is \frac{x}{3} =\frac{x^{2} }{x+5}

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, x=0 and x=\frac{5}{2} are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute x=0 in the original equation to check whether both sides of the equation are equal.

\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}

Thus, both sides of the equation are equal.

Hence x=0 is a true solution.

Now, Let us substitute x=\frac{5}{2} in the original equation to check whether both sides of the equation are equal.

\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}

Thus, both sides of the equation are equal.

Hence, x=\frac{5}{2} is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0
3 years ago
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