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brilliants [131]
4 years ago
15

Alfred has two cans containing biscuit dough. The cans are cylindrical and their dimensions (in inches) are as follows. • Can A:

h = 8 and r = 1 • Can B: h = 4 and r = 2 Which of the following statements about the volumes of the cans is true? A. The volume of can A is twice the volume of can B. B. The volumes of the two cans are equal. C. The volume of can A is four times the volume of can B. D. The volume of can B is twice the volume of can A.
Mathematics
1 answer:
kvv77 [185]4 years ago
4 0

Answer:

24

Step-by-step explanation:

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Solve absolute value equations and show work step by step ​please due tomorrow
Sergio039 [100]

Answer:

12) x = 10 or x = -10

13) b = 3 or b = -3.

14) r = 6 or r = -2

15)  n = 0 or -2

Step-by-step explanation:

12) Given, 4|x| + 3 = 43

Now, for x ≥ 0, |x| = x and for x < 0, |x| = -x

So, for x ≥ 0, the equation becomes 4x + 3 = 43

⇒ 4x = 40

⇒ x = 10

Again, for x < 0, we have - 4x + 3 = 43

⇒ - 4x = 40

⇒ x = - 10

Therefore, the solution of the equation is x = 10 or x = -10. (Answer)

13) Given, 3|b| + 5 = 14

Now, for b ≥ 0, |b| = b and for b < 0, |b| = -b

So, for b ≥ 0, the equation becomes 3b + 5 = 14

⇒ 3b = 9

⇒ b = 3

Again, for b < 0, we have - 3b + 5 = 14

⇒ - 3b = 9

⇒ b = - 3

Therefore, the solution of the equation is b = 3 or b = -3. (Answer)

14) 9|2r - 4| + 1 = 73

Now, for 2r - 4 ≥0 i.e. r ≥ 2, then

9(2r - 4) + 1 = 73

⇒ 2r - 4 = 8

⇒ 2r = 12

⇒ r = 6

Again, for (2r - 4) < 0 i.e. r < 2, then

9(4 - 2r) + 1 = 73

⇒ 4 - 2r = 8

⇒ 2r = - 4

⇒ r = -2

Hence, the solutions are r = 6 and r = -2  (Answer)

15) For, 10n + 10 ≥ 0 i.e. n ≥ -1, then

1 + 4(10n + 10) = 41

⇒ 10n + 10 =10

⇒ 10n = 0

⇒ n = 0

Again, for 10n + 10 < 0 i.e. n < -1, then

1 - 4(10n + 10) = 41

⇒ 10n + 10 = - 10

⇒ 10n = -20

⇒ n = -2  

Hence, the solution is n = 0 or -2 (Answer)

4 0
4 years ago
a shipping box will be filled with two different machine parts. one type of machine part weights 0.15 ponds and the other weight
gulaghasi [49]
\frac{x}{2} =0.15 hope so this helps

8 0
3 years ago
Graph the linear equation.find three points that solve the equation,then plot on the graph -3x++2y=11
Katarina [22]

-3x+2y=11\qquad\text{add 3x to both sides}\\\\2y=3x+11\qquad\text{divide both sides by 2}\\\\y=\dfrac{3}{2}x+\dfrac{11}{2}\\\\for\ x=1\to y=\dfrac{3}{2}(1)+\dfrac{11}{2}=\dfrac{3}{2}+\dfrac{11}{2}=\dfrac{14}{2}=7\to(1,\ 7)\\\\for\ x=-3\to y=\dfrac{3}{2}(-3)+\dfrac{11}{2}=-\dfrac{9}{2}+\dfrac{11}{2}=\dfrac{2}{2}=1\to(-3,\ 1)\\\\for\ x=-5\to y=\dfrac{3}{2}(-5)+\dfrac{11}{2}=-\dfrac{15}{2}+\dfrac{11}{2}=-\dfrac{4}{2}=-2\to(-5,\ -2)

3 0
4 years ago
What is the degree of f(x) = (x + 3)(x - 1)(2x + 2)?<br><br>A. 1 B.2 C.3 D.4
Semmy [17]

Answer:

I believe the answer is c) 3

Step-by-step explanation:

f(x) = (x + 3)(x - 1)(2x + 2)

x(x) + x(-1) + 3(x) + 3(-1)

f(x) = (x^2 - x + 3x - 3)(2x + 2)

f(x) = (x^2 + 2x - 3)(2x + 2)

2x(x^2) + 2x(2x) + 2x(-3) + 2(x^2) + 2(2x) + 2(-3)

f(x) = (2x^3 + 4x^2 - 6x + 2x^2 - 6)

<u>f(x) = (2x^</u><u>3</u><u> + 6x^2 - 6x - 6)</u>

4 0
3 years ago
Hello can you please help me posted picture of question
ollegr [7]
The correct option is (B) 4x^2 + 18x + 18

Explanation:
The area is given as:
(3+2x)(6+2x)

To find the polynomial just simplify it.
3(6+2x) + 2x(6+2x)

18 + 6x + 12x + 4x^2

4x^2 + 18x + 18
7 0
3 years ago
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