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Aleksandr [31]
3 years ago
10

A car’s stopping distance in feet is modeled by the equation d(v)=2.15vsquared over 58.4f, where v is the initial velocity of th

e car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.34, what is the approximate
Mathematics
2 answers:
Alexus [3.1K]3 years ago
7 0

Answer:(i dont know the answer but this person stopped the question early idk if it matters but the rest of it is)

approximate stopping distance of the car

A: 21 feet

B: 21 miles

C: 239 feet

D: 239 miles

i think that the answer was 239 feet

Step-by-step explanation:


frutty [35]3 years ago
3 0
According to your description, you can simply plug in all the numbers:

d(47) = 2.15 * 45^2 / (58.4*0.34) = 219.27 m
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A line parallel to your equation has the same slope, so it should be in the form:


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In the lottery game known as 6/36, a player picks six numbers from 1 to 36. (a) How many different ways are there for the player
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Step-by-step explanation:

Part A

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1947792

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3 0
3 years ago
In ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45. What is the value of the cosine of ∠X to the nearest hundredth?
kotegsom [21]

The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

Step-by-step explanation:

The given is,

                   In ΔWXY, ∠Y=90°

                        XW = 53

                         YX = 28

                        WY = 45

Step:1

             Ref the attachment,

             Given triangle XWY is right angled triangle.

             Trigonometric ratio's,

                              Cos ∅  = \frac{Adj}{Hyp}    

             For the given attachment, the trigonometric ratio becomes,

                              Cos ∅  = \frac{XY}{XW}.....................................(1)

             Let, ∠X = ∅

             Where, XY = 28

                         XW =  53

             Equation (1) becomes,

                                 Cos ∅  = \frac{28}{53}

                                 Cos ∅ = 0.5283

                                        ∅ = cos^{-1} (0.5283)

                                        ∅ = 58.109°

Result:

          The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

             

4 0
3 years ago
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