A car’s stopping distance in feet is modeled by the equation d(v)=2.15vsquared over 58.4f, where v is the initial velocity of th
e car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.34, what is the approximate
2 answers:
Answer:(i dont know the answer but this person stopped the question early idk if it matters but the rest of it is)
approximate stopping distance of the car
A: 21 feet
B: 21 miles
C: 239 feet
D: 239 miles
i think that the answer was 239 feet
Step-by-step explanation:
According to your description, you can simply plug in all the numbers:
d(47) = 2.15 * 45^2 / (58.4*0.34) = 219.27 m
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