Question

A car’s stopping distance in feet is modeled by the equation d(v)=2.15vsquared over 58.4f, where v is the initial velocity of the car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.34, what is the approximate

Answer 1

Answer:(i dont know the answer but this person stopped the question early idk if it matters but the rest of it is)

approximate stopping distance of the car

A: 21 feet

B: 21 miles

C: 239 feet

D: 239 miles

i think that the answer was 239 feet

Step-by-step explanation:

Answer 2

According to your description, you can simply plug in all the numbers:

d(47) = 2.15 * 45^2 / (58.4*0.34) = 219.27 m