All categories

3 years ago

Mr. Jackson took the 8th grade class on

Mathematics

2 answers:

timofeeve [1]3 years ago

4 0

Hi there! :)

Answer:

$\huge\boxed{\frac{17}{7} }$

Given ratio of 51 boys to 21 girls:

Write as a ratio:

$51 : 21$

Divide both terms by GCF, or 3:

$\frac{51}{3} : \frac{21}{3}$

$17 : 7$ or $\frac{17}{7}$

Therefore, the ratio is 17 boys to 7 girls, or $\boxed {\frac{17}{7}}$

Firdavs [7]3 years ago

3 0

Answer:

17/7

Step-by-step explanation:

the ratio would be 51/21 then to simplify divide both numbers by 3 to get 17/7

You might be interested in

the local weather report states that there is more than a 2/3 chance of rain for saturday. what is the likelihood that it with r

AlekseyPX

The chance of rain would be 67% through 100% I hope this helped ^^

5 0

4 years ago

(a) Explain what is wrong with the following ‘proof’:Statement:IfRis symmetric and transitive, thenRis reflexive."Proof":Suppose

barxatty [35]

Answer:

Step-by-step explanation:

Recall that, in this case, the subset of X for which R is defined is called the domain of R. The mistake occurs when we assume that the domain R is the whole set X, but it could happen that R is not defined for some elements of X.

Recall the following example:

X = {2,4,6}.

We can define R as follows {(2,2), (4,4), (2,4), (4,2)}. We can easily check that this is a transitive and symmetric relation, but since we don't have the element (6,6) it fails to be reflexive.

8 0

3 years ago

See your levels

Dafna11 [192]

Answer:

Step-by-step explanation:

if it cost 2,145 for the whole thing and 39 for each person 2,145 divide by 39= 55

8 0

3 years ago

Plz help thanks you

Stells [14]

Answer:9

Step-by-step explanation:

5 0

3 years ago

Use Simpson's Rule with n = 10 to estimate the arc length of the curve. Compare your answer with the value of the integral produ

SOVA2 [1]

$y=\ln(6+x^3)\implies y'=\dfrac{3x^2}{6+x^3}$

The arc length of the curve is

$\displaystyle\int_0^5\sqrt{1+\frac{9x^4}{(6+x^3)^2}}\,\mathrm dx$

which has a value of about 5.99086.

Let $f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}$ . Split up the interval of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [9/2, 5]

The left and right endpoints are given respectively by the sequences,

$\ell_i=\dfrac{i-1}2$

$r_i=\dfrac i2$

with $1\le i\le10$ .

These subintervals have midpoints given by

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

Over each subinterval, we approximate $f(x)$ with the quadratic polynomial

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that the integral we want to find can be estimated as

$\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that

$\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6$

so that the arc length is approximately

$\displaystyle\sum_{i=1}^{10}\frac{f(\ell_i)+4f(m_i)+f(r_i)}6\approx5.99086$

5 0

3 years ago