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2 years ago

Mr. Jackson took the 8th grade class on

Mathematics

2 answers:

timofeeve [1]2 years ago

4 0

Hi there! :)

Answer:

$\huge\boxed{\frac{17}{7} }$

Given ratio of 51 boys to 21 girls:

Write as a ratio:

$51 : 21$

Divide both terms by GCF, or 3:

$\frac{51}{3} : \frac{21}{3}$

$17 : 7$ or $\frac{17}{7}$

Therefore, the ratio is 17 boys to 7 girls, or $\boxed {\frac{17}{7}}$

Firdavs [7]2 years ago

3 0

Answer:

17/7

Step-by-step explanation:

the ratio would be 51/21 then to simplify divide both numbers by 3 to get 17/7

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2 years ago

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11111nata11111 [884]

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39.56%

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1 year ago

Read 2 more answers

The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$