A. The molarity of solution containing 5.2 g of sodium sulphate is 0.0732 M
B. The number of mole of sodium in the solution is 0.0732 mole
<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
- Mass of Na₂SO₄ = 5.2 g
- Molar mass of Na₂SO₄ = (23×2) + 32 + (16×4) = 142 g/mol
Mole = mass / molar mass
Mole of Na₂SO₄ = 5.2 / 142
Mole of Na₂SO₄ = 0.0366 mole
<h3>A. How to determine the molarity </h3>
- Mole of Na₂SO₄ = 0.0366 mole
- Volume = 500 mL = 500 / 1000 = 0.5 L
Molarity = mole / Volume
Molarity = 0.0366 / 0.5
Molarity = 0.0732 M
<h3>B. How to determine the mole of sodium (Na) </h3>
1 mole of Na₂SO₄ contains 2 moles of Na.
Therefore,
0.0366 mole of Na₂SO₄ will contain = 0.0366 × 2 = 0.0732 mole of Na
Thus, 0.0732 mole of Na is present in the solution.
Learn more about molarity:
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Answer; NO is the compound Nitrous Oxide whereas No is the metal Nobelium.
Explanation:
Answer:
Molecules
Explanation:
If you had more than one atom chemically bonded together, then regardless of the types of atoms that are bonded, you're going to have a molecule regardless.
PH is a measure of how acidic/basic water is. The range goes from 0 to 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. The pH of water is a very important measurement concerning water quality.
Answer:
Option 4 is correct (72 seconds)
Explanation:
Option 4 is correct (72 seconds)
The formula we are going to use is:
Where:
A is the final concentration
A_o is the initial concentration
k is the constant
t is the time
Half-Life=0.693/k
Half-life in our case=24 seconds
k=0.693/24
k=0.028875 s^-1
Since the concentration is decreased by 87.5 % which means only 12.5%(100-87.5%) is left.
The ratio 
will become 0.125
t≅ 72 seconds
