<span>1.16 moles/liter
The equation for freezing point depression in an ideal solution is
ΔTF = KF * b * i
where
ΔTF = depression in freezing point, defined as TF (pure) ⒠TF (solution). So in this case ΔTF = 2.15
KF = cryoscopic constant of the solvent (given as 1.86 âc/m)
b = molality of solute
i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1.
Solving for b, we get
ΔTF = KF * b * i
ΔTF/KF = b * i
ΔTF/(KF*i) = b
And substuting known values.
ΔTF/(KF*i) = b
2.15âc/(1.86âc/m * 1) = b
2.15/(1.86 1/m) = b
1.155913978 m = b
So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
i speak english . gracias!
Answer:
212.8 dm^3 or L
Explanation:
1 mole of any sub=6.02×10^23 molecules
X mole of O2=5.7×10^24 molecules
X mole=5.7×10^24/6.02×10^23
=9.5 mole
1 mole of any gas at stp=22.4 dm^3
Therefore, 9.5 mole of O2 will be 22.4×9.5
=212.8 dm^3
Steroids are lipids because they are hydrophobic and insoluble in water
The gravitational force between the objects depends on the mass of the objects and the distance between them.
