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3 years ago

2 out of 3 dogs weigh less than 20 pounds. What is the decimal equivalent for the number of dogs weighing under 20 pounds

Mathematics

1 answer:

Paha777 [63]3 years ago

4 0

Answer:

... 0.7 . . . or 0.67 . . . or 0.667 . . . or 0.6667 . . . or ...

Step-by-step explanation:

2/3 is a repeating decimal: 0.66666... Round where you like. The rounding is usually in the 2nd or 3rd decimal place, depending on the accuracy needed.

... 0.67 or 0.667 . . . . . the decimal fraction of dogs

_____

<em>Comment on wording</em>

The question asks for the "number of dogs". In the problem statement, we're told that number is 2 (out of 3). Actually, it can be any even integer number (out of 3/2 that many), up to 2/3 of the total dog population (which is estimated at over 520 million).

Had the problem asked for <em>the fraction of dogs</em>, then an appropriate answer is 0.67.

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kobusy [5.1K]

Answer:

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Step-by-step explanation:

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3 years ago

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almond37 [142]

Answer: The correct congruence statement is $\triangle QDJ\cong \triangle MCW$ .

Explanation:

It is given that A triangle Q D J. The base D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J.

The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.

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3 years ago

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Sonja [21]

Question

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Answer:

Step-by-step explanation:

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3 years ago

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2 years ago

The amount of time, in minutes, that a woman must wait for a cab is uniformly distributed between zero and 12 minutes, inclusive

murzikaleks [220]

Answer:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Step-by-step explanation:

Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:

$X \sim Unif (a=0, b =12)$

And we want to find the following probability:

$P(X$

And for this case we can use the cumulative distribution function given by:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

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3 years ago